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C # advanced programming (Fourth Edition)-Reading Notes (1)

I just started to learn C # And. NET and wrote some code. I feel that the basics are still very important. I want to learn C # advanced programming (Fourth Edition) carefully. With a thorough attitude, I will do some demos to verify what I don't know and what I feel is prone to errors. There will certainly be something wrong with your understanding. Please put it forward and make progress together. (The cod

iOS Programming (bilingual edition)-View-frame/bounds/center

coordinates of the view4. About the main window and the device screenThe device screen (Uiscreen.mainscreen ()) does not have a frame, but it has bounds.The main window does not have a parent view, but its frame can be set to the bounds of the screen.Let w = UIWindow (Frame:UIScreen.mainScreen (). Bounds)5. About the difference between frame and boundsWord is the former relative to the parent view, whereas the latter is relative to itself.Let's take a look at the picture, it's more intuitive.In

21.1 XMLHttpRequest Object "JavaScript Advanced Programming Third Edition"

form submissions by first setting the Content-type header information to application/x-www-form-urlencoded, which is the type of content at the time the form was submitted, followed by creating a string in the appropriate format. The 14th chapter has discussed the format of the POST data in the same format as the query string. If you need to serialize the data for a form in a page and then send it to the server via XHR, you can use the Serialize () function described in chapter 14th to create t

iOS Programming (bilingual edition)-View

1. What is a view?The view is displayed as a rectangular area on the phone, which is a subclass of UIView or UIView.Views can be either generated from Xib or generated in code.2. WindowsA window is a uiwindow or a subclass of it.The top level of the view structure is the app's window.The window must be filled with the screen of the device, so the frame of the window must be set to the bounds of the screen.(I'll explain the difference between frame and bounds later)The code is as follows:Objectiv

Linux-unix Advanced Programming (third edition) source code compilation (that is, header file apue.h How to use the problem) "Go"

caller. * Caller Specifies "Errnoflag". */ static void Err_doit (int errnoflag, int error, const char *fmt, va_list ap) /c2> { Char Buf[maxline]; vsnprintf (buf, MAXLINE, FMT, AP); if (errnoflag) snprintf (Buf+strlen (BUF), Maxline-strlen (BUF), ":%s", Strerror (Error)); strcat (buf, "\ n"); Fflush (stdout); /* In case stdout and stderr is the same * / Fputs (buf, stderr); Fflush (NULL); / * Flushes all stdio output streams * / } 6. Logout, restart7. Code file

"Update complete" Linux command line and Shell script Programming Daquan (3rd edition) reading notes 21-26 chapters

= 0;i = 1; does {total + = $i; i++} while (total Gawk ' {total =0;-(i = 1;i Chapter 23rd using other shellsYou can try to learn to use zsh and support modularity.24th. Writing a simple script utilitySlightly25th. Create DATABASE, Web, and e-mail related scriptsThe side that writes the script to MySQL is available:MySQL mytest-u test Show tables;SELECT * FROM Employees where salary > 40000;Eofecho "This is a text message." | mail-s "Subject" [email protected]-b [email protected]-C [email protec

1025:c Language Programming Tutorial (third Edition) after class exercise 7.3

The title describes the sum of the diagonal elements of a 3x3 matrix. Input matrix output main diagonal sub-diagonal element and sample input1 2 31 1 13 2 1Sample output3 7Hint Source#includeint main(){int a[9];int x,y,i;for(i=0;iscanf("%d",a+i);x=a[0]+a[4]+a[8];y=a[2]+a[4]+a[6];printf("%d %d\n",x,y);} 1025:c Language Programming Tutorial (third Edition) after class exercise 7.3

1020:c Language Programming Tutorial (third Edition) after class exercise 6.9

The title describes a ball from the M-meter height of the free fall, each landing after the return of the original height of half, and then fall. How high does it bounce when it lands on nth time? How many meters are there? Leave two-bit decimal input m n output how high does it bounce when it lands on nth time? How many meters are there? Keep two decimal places separated by spaces and put in one line sample input1000 5Sample output31.25 2875.00Hint Source#includeint main(){int m,n,i;float h,l=0

JavaScript Advanced Programming (3rd edition)

Chapter 3rd Basic ConceptsIn this chapter: syntax, data types, flow control statements, functions3.1 Syntax3.1.1 Case Sensitive3.1.2 IdentifierUse Hump case Format1) The first character must be a letter, an underscore (_), or a dollar sign ($);2) Other characters can be letters, underscores, dollar signs, or numbers.3.1.3 Notes3.1.4 Strict mode"Use Strict"3.1.5 Statements3.2 keywords and reserved words3.3 VariablesVarLocal variables3.4 Data types5 Simple data types (also known as base data types

C + + Primer plus Sixth Edition programming Exercise---Chapter 4th composite types

1.#include int main (int argc, char* argv[]){Char firstname[50] = {0};Char lastname[50] = {0};char grade;int age;Std::cout Std::cin.getline (FirstName, 49);Std::cout Std::cin.getline (LastName, 49);Std::cout Std::cin >> grade;Std::cout Std::cin >> age;Std::cout Std::cout Std::cout return 0;}C + + Primer plus Sixth Edition programming Exercise---Chapter 4th composite types

Getting Started with Shell Programming (second Edition) (middle)

password is empty usersAwk-f: ' Length ($) ==0 {print $} '/etc/shadow#ps aux |Grep-v Root | awk ' {print $} 'Demo Sample -awk.sh#!/bin/bash# a test script for desplay users infomation/bin/echo-n "Please input A username:" Read Username/bin/grep $use rname/etc/passwd >/dev/null 2>/dev/nullif [$?-eq 0]then/bin/echo "username is: $username" Else/bin/echo "User: $username is not exits." Exit 1fi/bin/echo# list/etc/passwd infouserinfo= '/bin/grep ^ $username: x/etc/passwd ' uid= ' echo $userinfo

C + + Programming (4th edition) Reading notes _ basic knowledge

Assigning values to variablesThe commonly used variable assignment is to use "=" to assign values.1 int 2;However, if you assign a floating-point number to I, it will result in a loss of precision, preferably in C + + using the initialization list of the way "{}" to assign a value to the variable, so as to ensure that some types of information loss may cause the conversion of the type1 #include 2usingnamespace std; 3 4 int Main () {5 int I {2.3}; 6 return 0 ; 7 }For example, the compile

JavaScript DOM Programming Art (2nd edition) reading notes (4)

which are contained in the array returned by the ChildNodes property.However, each node has a NodeType property. The NodeType attribute has a total of 12 desirable values, but only 3 of them have value: The NodeType attribute value of the element node is 1, the property node's NodeType property value is 2, and the NodeType property value of the text node is 3.If you want to change the value of a text node, use the NodeValue property provided by the DOM.Array element Childnodes[0] There is a mor

1018:c Language Programming Tutorial (third Edition) after class exercise 6.8

The title description has a fractional sequence: 2/1 3/2 5/3 8/5 13/8 21/13 ... The sum of the first n items of this sequence is calculated, and two decimal places are reserved. Input n output series top N and sample input10Sample output16.481#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 6 intN, M =2, n =1, I;7 floats =0;8scanf"%d", N);9 for(i =0; i )Ten { One intT; As + = (float) m/N; -t =m; -m = n +m; then =T; - } - -printf"%.2f\n", s); + return 0;

1015:c Language Programming Tutorial (third Edition) after class exercise 6.5

The title describes the sum of the following three numbers, preserving the 1~b of the sum of the squares and 1~c of the 2-bit decimal 1~a and the input a B c output 1+2+...+a + 1^2+2^2+...+b^2 + 1/1+1/2+...+1/c Sample input100 50 10Sample output47977.931 intMainintargcChar Const*argv[])2 {3 4 intA, B, C, I;5 floatS1 =0, S2 =0, S3 =0;6 7scanf"%d%d%d", a, b, c);8 9 for(i =1; I )Ten { OneS1 + =i; A } - - for(i =1; I ) the { -S2 + = i *i; - } - + for(i =1

Java Programming Ideas Fourth Edition Chapter three key exercises

reference type, when he is directly assigned to the value of the corresponding reference position is assigned to the string variable, so, two times the result is true. If you assign a value with the new String (), the result will be different. Write a program that simulates the result of tossing a coinPackage Net.mindview.operators;import Java.util.random;importStaticnet.mindview.util.print.*; Public classThrowcron { Public Static voidMain (string[] args) {Random num=NewRandom (); intA = Num.

JavaScript Advanced Programming (Third Edition) Chapter fourth variables, scope and memory issues

JavaScript variables can be used to hold two types of values: primitive type values and reference type values. Basic type values and reference type values have the following characteristics: The base type value occupies a fixed amount of space in memory and is therefore stored in the stack memory; Copying a base type value from one variable to another creates a copy of the value; The value of a reference type is an object that is stored in heap memory; A reference-type-worth

JavaScript-javascript DOM Programming Art (2nd edition)

/* Progressive enhancement smooth degraded web page structure layer (structural layer): HTML presentation layer (presentation layer): CSS JavaScript-javascript DOM Programming Art (2nd edition)

Java Programming Ideas Fourth Edition Nineth Chapter

()");} @Overridepublic void A2 () {//TODO auto-generated Method StubSystem.out.println ("A2 ()");} @Overridepublic void B1 () {//TODO auto-generated method StubSystem.out.println ("B1 ()");} @Overridepublic void B2 () {//TODO auto-generated method StubSystem.out.println ("B2 ()");} @Overridepublic void C1 () {//TODO auto-generated method StubSystem.out.println ("C1 () ");} @Overridepublic void C2 () {//TODO auto-generated method StubSystem.out.println ("C2 ()");} @Overridepublic void ABC () {//

Java Programming Ideas (Fourth Edition) * Chapter II Personal exercises

Create a class that contains an int field and a char field that are not initialized and print them out to verify that Java performs the default initialization.public class Domtest{int I;char c;public domtest () {System.out.println ("i=" +i+ "\nc=[" +c+ "]" + "\ n []");/** * Print result as follows I =0 c=[] []//only for comparison reference */}/** * @param args */public static void main (string[] args) {new domtest ();}}Java Programming Ideas (Fourt

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