replay backpack

Last week Jason Fried sent a preview of the backpack version of golden ticket. Today, the long-awaited backpack is officially launched. The following are some reviews after use. 37signals works are well known for their ease of use and user experience. This release of backpack is the third set of 37signals (the previous product was Basecamp, ta-da list) web serv

Continued: In Unity3d, the idea of dealing with backpacks in the game is that each lattice of a backpack is a clickable object, and a single lattice can be made into one Prefabs is then added to the game, and each grid has a logic judgment, whether there are items in the current grid, whether the current grid is empty My approach is not to dynamically generate objects, but to manually load backpack objects

0-1 backpack Problem: There are N items and a backpack with a capacity of V. The value of item I is c [I], and the weight is w [I]. Solving which items are loaded into a backpack can make the total weight of these items not exceed the size of the backpack, and the total value is the largest. This problem is characteriz

DescriptionSuppose you now have cash cash, there are n kinds of goods, given you their respective price and quantity. If you want to buy as many items as possible, ask for the total value of the goods you can buy the most.Sample Input735 3 4 125 6 5 3 350633 4 500 30 6 100 1 5 0 1735 00 3 10 100 10 50 10 10Sample Output73563000ExercisesRecently really in water title Yes WW(incredibly shy to say)Inexplicably because cash==0| | The situation in n==0 wa two times ... Just don't write it, Qwq.It's j

Topic:First, by limiting the height from small to large sort, will not affect the feasible solution, but not the sorting may be the correct situation;When scrolling an array with%2, be sure to pay attention to each copy of the situation, because this WA several times.The code is as follows:#include #include#include#includeusing namespacestd;intk,mx;BOOLf[3][400005];structn{intH,a,c;} p[405];BOOLCMP (N x,n y) {returnx.ay.a;}intMain () {scanf ("%d",k); for(intI=1; i) scanf ("%d%d%d", p[i].h,p[i].

Meaning to a N-node tree, the node number is 1~n, the root node is 1, and each node has a weight value. Starting from the root node, go no more than k step, ask the maximum number of weights can be obtained? Ideas Because it's a bit like uva-1407 caves, I didn't think about AC for a long time, but because of the initialization problem WA twice F (i, J, 0): Represents the subtree I, walks the J times, and ultimately does not have to return to the I point to obtain the maximum total weight F (I, J

Typical 01 backpack. Q: Tell you the height of all cows and the height of the shed, ask the minimum difference how much. Just start to read the wrong title, WA a lot of times, I think is the height of cattle can not exceed B, can be the original title is said to exceed the minimum height, sad reminders. #include

bearing C1,C2, asking how many times it will take to carry the furniture. Thinking of solving problems Bundle n pieces of furniture, use 1,0 to indicate whether the current state chooses this furniture, carries on the state compression;Then the total number of binding methods that is the total number of States is (1In the mark[] in the selection of independent (does not contain the same furniture) bundle status of 01 backpack, each bundle state I is

Title: Vijos P1836hys and Tanabata festival big battle Test instructions n objects, per value VI, specific gravity PI, total capacity 100 Analysis: Similar to the weight of the Backpack pi is a real number, not as subscript, so change the DP object Will find the maximum value in capacity 100 → to find the minimum capacity of the corresponding value, Then the value of the first ≤100 of the volume, which is the highest value of the value that meets the

Title Description DescriptionThe backpack volume is V, gives n items, each item occupies a volume of VI, the value of WI, each item can take up to 1 pieces, or the maximum number of MI pieces (Mi > 1), or the amount of unlimited, in the total volume of the items installed under the premise of the contents of the value of the goods and the largest value of what. Enter a description input DescriptionThe first line two number n,v, the following n lines e

Solution: At first thought this accord with the optimal sub-structure of the dynamic planning, but later looked at other people's solution found that does not conform to the optimal sub-structure, can not transfer all the state. Because maybe I picked the front one. But if I choose the other one plus the better, this time chose not to choose another because it has disappeared, this time can be done with 01 backpack and a vector array to record the pat

It's a classic complete backpack problem.My Code /* id:wangxin12 prog:inflate lang:c++ */ #include --------------------------------------------------------------------------------------------------------------- --------- The more points students score in our contests, the happier we here at the Usaco is. We try to design our contests so this people can score as many points as possible, and would like your assistance. We have several categorie