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Road Search (Jiangxi website construction) to provide you with 100M free space services, the following is their space introduction: Space Quote Price 0 yuan/year Configuration Web Space size 100M

suitable for such a newcomer like me, So I began to study here, and joined the platform of the Learning Group (244901223), in the 2 group of teachers will share some knowledge to us, we have problems can also ask questions in the group, to be solved and help. To say the real words, this year this free and willing to share knowledge of the platform is really not much, looking back to see their own road, no

++; - if(!road[i].l) About { $road[i].bj=1; -js2++; - } - HB (x, y); A } + if(js1==n-1) Break; the } - if(js1!=n-1|| Js2>t) $ { theprintf"No solution\n"); theExit0); the } theSort (road+1, road+1+m,px2); -js1=0, js2=0; in for(intI=1; ii; the

Specific title: https://vjudge.net/problem/HYSBZ-3624DescriptionA kingdom has n cities and M-strips of road, some of which are cobblestone roads and some are cement road. Now the king has to choose as few roads as possible for free, and make every two cities a free route. The king intends to keep just the K-Cobblestone

3624: [Apio2008] Free road time limit:2 Sec Memory limit:128 mbsec Special Judgesubmit:111 solved:49[Submit] [Status] DescriptionInputOutputSample Input5 7 21 3 04 5 13 2 05 3 14 3 01 2 14 2 1Sample Output3 2 04 3 05 3 11 2 1 or look at the online standard ..... The practice of this problem is first 1 side priority, do the spanning tree, if the number of 0 sides is greater than k no solution, or if

,FB); the } the for(inti=r;i) the if(TVis[i]) - { the intFa=find (edge[i].u), fb=find (EDGE[I].V); the if(fa!=FB) the {94 Unionset (FA,FB); thevis[i]=1; thet++; the }98 } About if(tk) - {101Puts"No solution");102 return;103 }104 //first select the cobblestone path you want, and then fill it with other cobblestone paths the 106 for(intI=1; i)107 {108 intFa=find (edge[i].u

Course Study Address: http://www.xuetuwuyou.com/course/228The course out of self-study, worry-free network: http://www.xuetuwuyou.comLecturer: Watermelon TeacherCourse Catalogue:1th, demand analysis2nd Lecture, website demoAnalysis of the 3rd lecture and technology selection4th, Technology Selection Supplement5th, the overall structure of the project6th, the three-tier architecture of the project7th, front-end JSSDK process8th Lecture, JSSDK event typ

=Find (v); if(x==y)Continue; FA[X]=y; Ans[++p]=b[i]; flag[i]=1; if(++cnt = = N1) Break; } if(P > K | | cnt 1) {puts ("No solution");return 0;} for(intI=1; ii; for(intI=1; ifind (ANS[I].V); CNT=p; if(cnt for(intI=1; iif(!Flag[i]) {u=B[I].U, v=b[i].v; intX=find (u), y=Find (v); if(x==y)Continue; FA[X]=y; ans[++cnt]=B[i]; if(cnt = = k) Break; } for(intI=1; i) {u=A[I].U, v=a[i].v; intX=find (u), y=Find (v); if(x==y)Continue; FA[X]=y; ans[++cnt]=A[i]; if(cnt = = N1) Break; } for(intI=1;

Instructor Homepage: http://edu.51cto.com/lecturer/7787419.html"Teacher Wangjin"Microsoft Certified Gold Lecturer, senior Microsoft Technical expert, Microsoft pre-sales consultant. With more than seven years of experience in Microsoft teaching and project experience, in the course to integrate a wealth of business case, so that the course more practical, coupled with humorous atmosphere of the course, so that students in the joy of learning, case understanding, practice in improving. Open Cla

Http://acm.hdu.edu.cn/showproblem.php?pid=1224The basis for finding the longest path and recording paths.Feel Dijstra than SPFA easy to use, WA two times.#include To find the longest road is a bit like the longest ascending sub-sequence, and then take the longest ascending sub-sequence of water.#include HDU 1224 free DIY tour (longest road/DP)

} - - intMain () { - - intn = Read (), M = Read (), k =read (); - in intB =0, W = m +1; - for(intI=1; ii) { to intU = Read (), V = Read (), C =read (); + if(c = =1) E[++b] =Edge (u,v); - ElseE[--W] =Edge (u,v); the } * $ for(intI=1; ii;Panax Notoginseng - inttot =0; the for(intI=1; ii) { + intU = Find (e[i].u), V =find (E[I].V); A if(U = = v)Continue; theFa[u] =v; + if(i > B) vis[i] =true, Q[++to

--] +'0'); $ } - - the intFIND_FA (intx) { - returnFA[X] = = x? X:FA[X] =Find_fa (fa[x]);Wuyi } the - intMain () { Wu intI, X, Y, F, L, R, FA1, FA2; -Len = Fread (buf,1, MaxLen, stdin); AboutBuf[len] =' '; $n = Read (), M = Read (), k =read (); - for(i =1, L =0, R = m +1; I i) { -x = Read (), y = Read (), F =read (); - if(f) E[++l] =edges (x, y); A ElseE[--R] =edges (x, y); + } the - for(i =1; I i; $ for(i =1; I i) the if((FA1 = Find