Tell a sad story!
These days are stepping up time to learn stl! The map was barely understood a little yesterday. (The premise of the story)
Today, came to the platform ready to brush about map, the teacher recommended a problem. Said to be about map. And then.. No!!
Later, Baidu. A moment of force! What the heck!
I hereby ask for advice!
IP Aggregation
Problem Description
Today's world, the network has been everywhere, the small bear because made a mistake, when the degree of the company's network administrator, he has a large number of IP list, the small bear want to know in a fixed subnet mask, how many network address. The network address is the result of the bitwise AND operation of the subnet mask and IP address, for example:
Subnet Mask: a.b.c.d
IP Address: a.b.c.d
Network address: (A&A). (b/b). (c&c). (d&d)
Input
The first line contains an integer tt t, ( 1≤T≤50) (1 \leq T \leq) (1≤t≤50) represents the number of groups of test data,
Next the TTT Group test data. Each set of test data contains several rows,
First row two positive integersN (1≤n≤1000,1≤m≤50), MN (1 \leq N \leq, 1 \leq m \leq), MN(1≤N≤1000,1≤m≤50),M. Next NNn lines, one string per line, representing an IP address,
And NextMmM rows, one string per line representing the subnet mask. Both the IP address and the subnet mask are usedA.b.c.da. B.c.dA. B. C. The form of D, where a,b,c,da,b,c,dA,B,C,d are all nonnegative integers and less than or equal to 255.
Output
For each set of test data, output two lines:
The first line of output: "Case #i:". III represents the test data for Group II I.
The second line outputs the results of the test data, and for each subnet mask in each set of data, the number of network addresses that are output under this subnet mask.
Sample Input
25 2192.168.1.0192.168.1.101192.168.2.5192.168.2.7202.14.27.235255.255.255.0255.255.0.04 2127.127.0.110.134.52.0127.0.10.110.134.0.2235.235.0.01.57.16.0
Sample Output
Case #1:32Case #2:34
Code:
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <set>
#include <vector>
#include <map>
using namespace Std;
const int maxn=1100;
int A[MAXN];
int B[MAXN];
int C[MAXN];
int D[MAXN];
Map<long long,int> m;
int main ()
{
int t;
scanf ("%d", &t);
for (int te=1;te<=t;te++)
{
int n,m;
scanf ("%d%d", &n,&m);
for (int i=0;i<n;i++) scanf ("%d.%d.%d.%d", &a[i],&b[i],&c[i],&d[i]);
printf ("Case #%d:\n", TE);
int a,b,c,d;
int ans;
a long long temp;
for (int i=1;i<=m;i++)
{
M.clear ();
ans=0;
scanf ("%d.%d.%d.%d", &a,&b,&c,&d);
for (int j=0;j<n;j++)
{
Temp=0;
temp=temp*1000+ (A[j]&a);
temp=temp*1000+ (B[J]&B);
temp=temp*1000+ (C[J]&C);
temp=temp*1000+ (D[J]&D);
if (!m[temp])
{
ans++;
M[temp]=1;
}
}
printf ("%d\n", ans);
}
}
return 0;
}
Ask the great God to comment!!
C++TSL's Map container (sad story)