(Android Studio) 8.16 extract parameter objects
Some parameters always appear at the same time. Several methods may use such a set of parameters. To avoid too long parameter lists and avoid repeated code, we can extract these parameters into parameter objects, this parameter object is used to replace the original input parameter.
Procedure:
? Menu Bar: Refactor-> Extract-> Parameter Object...
Example:
Before extracting parameter objects:
public class TestExtract { private void getAndroidInfo(String serialNumber, String packageName, String versionName, String versionCode){ DeviceInfo deviceInfo = new DeviceInfo(); deviceInfo.setSerialNumber(serialNumber); PackageInfo packageInfo = new PackageInfo(); packageInfo.setPackageName(packageName); }}
Step 2: select all parameters of the getAndroidInfo Parameter-> execution menu bar: Refactor-> Extract-> Parameter Object... -> The parameter configuration dialog box is displayed.
Step 2: In this example, create an internal class named AndroidInfo. All parameters are extracted by default-> Refactor
After the parameter object is extracted:
public class TestExtract { private void getAndroidInfo(AndroidInfo androidInfo){ DeviceInfo deviceInfo = new DeviceInfo(); deviceInfo.setSerialNumber(androidInfo.getSerialNumber()); PackageInfo packageInfo = new PackageInfo(); packageInfo.setPackageName(androidInfo.getPackageName()); } private static class AndroidInfo { private final String serialNumber; private final String packageName; private final String versionName; private final String versionCode; private AndroidInfo(String serialNumber, String packageName, String versionName, String versionCode) { this.serialNumber = serialNumber; this.packageName = packageName; this.versionName = versionName; this.versionCode = versionCode; } public String getSerialNumber() { return serialNumber; } public String getPackageName() { return packageName; } public String getVersionName() { return versionName; } public String getVersionCode() { return versionCode; } }}