Java basic------Hundred dollar buy hundred chicken problem

Problem Description: Rooster every 3 Yuan, hen every 5 yuan, chicken three only one yuan, ask 100 yuan to buy 100 chickens have several buy method?

public static void Main (string[] args) {
int count=0; Total scheme number with Count records
Suppose I means buy the number of hens, j means buy the number of cocks, k means buy chickens number
for (int i=0;i<=100/5;i++) {
for (int j=0;j<=100/3;j++) {
for (int k=0;k<=100;k+=3) {//This ensures that the number of chickens is a multiple of 3. The only way to spend money is to be an integer, not a decimal.
if (i+j+k==num && I*5+j*3+k/3==money) {
count++;
System.out.println ("+count +" scheme: Number of hens: "+ i +", Rooster Number: "+ j +", Number of chickens: "+ K);"
}
}
}
}
SYSTEM.OUT.PRINTLN ("Total" + count + "kind of buy Method!") ");
}

Expand here for spending money to buy num Chicken buying Method!!!

public static void Main (string[] args) {
Scanner scan=new Scanner (system.in);
System.out.println ("Please enter the total number of chickens you wish to buy (integers):");
int Num=scan.nextint ();
System.out.println ("Please enter how much you want to pay for these chickens (integers):");
int Money=scan.nextint ();

int count=0; Total scheme number with Count records
Suppose I means buy the number of hens, j means buy the number of cocks, k means buy chickens number
for (int i=0;i<=money/5;i++) {//i is the number of hens, assuming that all money buys a hen, you can buy up to MONEY/5, so I take the value range of 0-MONEY/5
for (int j=0;j<=money/3;j++) {//j represents the number of cocks, assuming that all money buys a rooster, you can buy up to MONEY/3; So the value range of J is 0-MONEY/3
for (int k=0;k<=money*3;k+=3{//k is the number of chicks, assuming that all money buys chickens, you can buy up to money*3, so the value range for K is 0-money*3
if (i+j+k==num && I*5+j*3+k/3==money) {//Note: The number of chicks must be 3 multiples to guarantee that the money spent is an integer, not a decimal condition.
count++;
System.out.println ("+count +" scheme: Number of hens: "+ i +", Rooster Number: "+ j +", Number of chickens: "+ K);"
}
}
}
}
SYSTEM.OUT.PRINTLN ("Total" + count + "kind of buy Method!") ");
}

Attention:

This code snippet (snippet 1):

for (int k=0;k<=money*3; k+=3) {
if (i+j+k==num && i*5+j*3+k/3==money) {　　

Equivalent to (Code Snippet 2):

for (int k=0;k<=money*3; k++) {
if (i+j+k==num && k%3==0 && i*5+j*3+k/3==money) {

Code Snippet 1 is more efficient than code snippet 2, so it is recommended that you use code Snippet 1.

Java basic------Hundred dollar buy hundred chicken problem