Fzu 1650 1752 a^b MoD C

Source: Internet
Author: User

accept:822 submit:3560
Time limit:1000 mSec Memory limit:32768 KB problem Description

Given A,b,c, you should quickly calculate the result of A^b mod C. (1<=a,b,c<2^63).

Input

There is multiply testcases. Each testcase, there are one line contains three integers A, B and C, separated by A single space.

Output

For each testcase, output an integer, denotes the result of A^b mod C.

Sample INPUT3 2 Sample Output

124

This problem because the data is relatively large, directly with the fast power template will be super unsigned long long range, so the same idea to calculate a*b/%c. Can be seen as a template. Enter with%llu or%i64u.

#include <stdio.h> #include <string.h> #define LL unsigned __int64ll mul (ll a,ll b,ll c)   //With the idea of a fast power to seek a*b% C Prevent cross-border  {        ll ret=0,tmp=a%c;        while (b)        {            if (b&1)                if ((ret+=tmp) >=c)                    ret-=c;            if ((tmp<<=1) >=c)                tmp-=c;            b>>=1;        }         return ret;    }  ll F (ll A,ll B,ll c) {ll ans=1;a=a%c;while (b>0) {if (b%2==1) {Ans=mul (ans,a,c);} B=b/2;a=mul (a,a,c);} return ans;} int main () {ll n,m,i,j,a,b,c;while (scanf ("%i64u%i64u%i64u", &a,&b,&c)!=eof) {printf ("%i64u\n", F (a,b,c)) ;} return 0;}


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Fzu 1650 1752 a^b MoD C

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