How to obtain the IP address of a mobile phone in android4.0

Code for obtaining the mobile phone IP Address:

public static String getLocalIpAddress(){try{ for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) { NetworkInterface intf = en.nextElement();                  for (Enumeration<InetAddress> enumIpAddr = intf                          .getInetAddresses(); enumIpAddr.hasMoreElements();) {                      InetAddress inetAddress = enumIpAddr.nextElement();                      if (!inetAddress.isLoopbackAddress()) {                                              return inetAddress.getHostAddress().toString();                      }                  }   }}catch (SocketException e) {// TODO: handle exceptionUtils.log("WifiPreference IpAddress---error-" + e.toString());}return null; }

However, in 4.0, an IP address similar to fe80: b607: f9ff: fee5: ipve is displayed. This is an IPV6 address. We need to obtain an IPV4 address, therefore, add a judgment in the appeal code.

InetAddressUtils.isIPv4Address(inetAddress.getHostAddress())

The complete code is as follows:

public static String getLocalIpAddress(){try{ for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) { NetworkInterface intf = en.nextElement();                  for (Enumeration<InetAddress> enumIpAddr = intf                          .getInetAddresses(); enumIpAddr.hasMoreElements();) {                      InetAddress inetAddress = enumIpAddr.nextElement();                      if (!inetAddress.isLoopbackAddress() && InetAddressUtils.isIPv4Address(inetAddress.getHostAddress())) {                                              return inetAddress.getHostAddress().toString();                      }                  }   }}catch (SocketException e) {// TODO: handle exceptionUtils.log("WifiPreference IpAddress---error-" + e.toString());}return null; }