Huawei computer questions

Parse the 9-in-9 format. The 11-in-11 string is a 10-in-10 numeric output. The length of the input string's valid bits (0v0012345678) is no more than 8 bits. The previous 00 is not a valid bits. After resolution, it is output in decimal format.
-1 is returned if an invalid string is parsed.

9 hexadecimal:
The value range of the 9-digit number is 0, 1, 2, 3, 4, 5, 6, 7, and 8.
9: 0 V or 0 V
Example of a 9-digit system: 0v11 0v564 0v123 0v0784 0v0 0 V 0 V
9-digit error instance: 0v923 0vt12 00v21 0123
9-to-10: 0v11-> 10
0v564-> 463
 
11 hexadecimal:
The range of numbers in the 11 hexadecimal format: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A ()
The start of the 11 hexadecimal format is 0 w or 0 w.
Correct 11-digit example: 0w11 0w564 0w123 0w0a8a 0 w 0 w
11 hexadecimal error instance: 0wb923 0 wvaa 00w21 0wax123
Convert the hexadecimal value to the hexadecimal value:
0w11-> 12
0w564-> 675

 

 

#include <math.h>#include<iostream>#include <string>using namespace std;void main(){        string str;    cin>>str;    int len=str.length();        char *ch=new char[len];    for (int i=0;i<len;i++)    {        ch[i]=str[i];    }    int iRet=0;    if (ch[0]==‘0‘&&(ch[1]==‘v‘||ch[1]==‘V‘))    {        for (int i=len-1;i>1;i--)        {            if (ch[i]>‘8‘||ch[i]<‘0‘)            {                cout<<-1;                return;            }            iRet+=(ch[i]-‘0‘)*((int)pow(9.0,len-1-i));        }    }    else if (ch[0]==‘0‘&&(ch[1]==‘w‘||ch[1]==‘W‘))    {        for (int i=len-1;i>1;i--)        {            if (ch[i]!=‘a‘&&ch[i]!=‘A‘&&(ch[i]>‘9‘||ch[i]<‘0‘))            {                cout<<-1;                return;            }            if (ch[i]==‘a‘||ch[i]==‘A‘)            {                ch[i]=‘0‘+10;            }            iRet+=(ch[i]-‘0‘)*((int)pow(11.0,len-1-i));        }    }    else         {             cout<<-1;              return;         }    cout<<iRet;    }