I don't know.

I don't know.

/* The description of as we all know won't help me. Oh, of course, this time I still don't. I just want you to translate the numbers for me. The so-called translation is to read a number in Chinese. It's easy, please be patient. The numbers are in Chinese: 0, 1, 2, 3, Si, Wu, Lu, Wei, Wei, Shi, Xiao, Xiao, Min, and Min. make sure that the input value is within the int range. The output is written in the Chinese language I gave you. The sample is input. The sample is output. * // * Enter a four-digit number: 1245, and. */# include <stdio. h> # include "string. h "int main (int argc, const char * argv []) {// insert code here... int n; printf ("Enter 4 digits: \ n"); scanf ("% d", & n); int a, B, c, d; // single digit d = n % 10; // ten digits c = n % 100/10; // hundreds of BITs B = n % 1000/100; // thousands of bits a = n/1000; char * s [255] = {"zero", "one", "two", "yellow", "Si", "Wu", "Lu", "Lu ", "condition", "condition"}; if (a = 0 & B = 0 & c = 0 & d! = 0) {printf ("% s \ n", s [d]);} else if (a = 0 & B = 0 & c! = 0 & d! = 0) {printf ("% s ten % s \ n", s [c], s [d]);} else if (a = 0 & B = 0 & c! = 0 & d = 0) {printf ("% s ten \ n", s [d]);} else if (a = 0 & B! = 0 & c! = 0 & d! = 0) {printf ("% s hundred % s ten % s \ n", s [B], s [c], s [d]);} else if (a = 0 & B! = 0 & c! = 0 & d = 0) {printf ("% s hundreds % s ten \ n", s [B], s [c]);} else if (a = 0 & B! = 0 & c = 0 & d = 0) {printf ("% s hundred \ n", s [B]);} else if (! = 0 & B! = 0 & c! = 0 & d! = 0) {printf ("% s thousands % s hundreds % s ten % s \ n", s [a], s [B], s [c], s [d]);} else if (! = 0 & B! = 0 & c! = 0 & d = 0) {printf ("% s thousands % s hundreds % s ten \ n", s [a], s [B], s [c]);} else if (! = 0 & B! = 0 & c = 0 & d = 0) {printf ("% s \ n", s [a], s [B]);} else if (! = 0 & B = 0 & c = 0 & d = 0) {printf ("% s thousands \ n", s [a]);} else if (! = 0 & B = 0 & c = 0 & d! = 0) {printf ("% s thousands of zeros % s \ n", s [a], s [d]);} else {printf ("enter the correct number !! \ N ") ;}return 0 ;}