Intersection of all line segments-Primary article __ Computer vision

Intersection of all line segments-primary articles

tags (space-delimited): Computer vision, Graphic science

Intersection of all line segments-primary articles

Reference: "Computational geometry-Algorithms and Applications" Deng Junhui translation Tsinghua University Press

This paper presents a small example of how to compute the intersection point of all line segments without considering the use of position relationships in the horizontal x direction to reduce complexity, for example:

The State structure S (1) scan line first passes the upper point of Line 1, and the segment 1 enters S={1}

(2) The scan line calculates the intersection point of line segment 2 with s in the upper end of Line 2, gets a segment 2 enters s={1,2}

(3) The scan line passes the upper point of line 4 to compute the intersection line between 4 and S of all segments: Wireless segment 4 enters s={1,2,4}
(4) The scan line passes the top point of line 3
Calculates the intersection point of Line 3 with all line segments in S: B and C segment 3 entering s4={1,2,4,3}
(5) Scan line through the lower point of line 1
Segment 1 out State structure, s={2,4,3}
(6) Scan line through the lower point of line 2
Segment 2 out state structure, s={4,3}
(7) Scan line through the lower point of line 3
Segment 3 out state structure, s={4}
(8) Scan line through the lower point of line 4
Line 4 out of state structure, s={}, that is, the state structure is empty
(9) Scan line first through the end point of line 5
Segment 5 into S={5}
(10) The scan line passes the top point of line 6
Calculates the intersection of line 6 with all segments in S: D segment 6 enters s={5,6}
(11) The scan line passes the top point of line 7
Calculates the intersection of Line 7 with all line segments in S: Wireless segment 7 enters s={5,6,7}
(12) The scan line passes the top point of line 8
Calculates the intersection point of Line 8 with all line segments in S: E segment 8 enters s={5,6,7,8}
(13) The scanning line passes the lower point of line 5, the line segment is 5 out, s={6,7,8}
(14) The scanning line passes the lower point of line 7, the line segment is 7 out, s13={6,8}
(15) The scanning line passes the lower point of line 8, the line segment is 8 out, s14={6}
(16) The scanning line passes the lower point of line 6, the line segment is 8 out, s15={}
At this point, all corner points are solved, and the {A, B, C, D, E}