Java Fundamentals 03

Source: Internet
Author: User

1. Let the user enter a score (0-100), determine which range the score belongs to and output the results (first draw a flowchart in Word)

(90-100->a 70-90->b 60-70->c <60--d)

Import Java.util.Scanner;

public class Problem1 {

public static void Main (string[] args) {

Scanner scan=new Scanner (system.in);

SYSTEM.OUT.PRINTLN ("Please output a score (0-100):");

int Score=scan.nextint ();

if (score<=100&&score>=90) {

System.out.println ("A");

}else if (score<90&&score>=70) {

System.out.println ("B");

}else if (score<70&&score>=60) {

System.out.println ("C");

}else if (score<60&&score>=0) {

System.out.println ("D");

}else{

SYSTEM.OUT.PRINTLN ("You have entered the wrong score.) ");

}

}

}

2. Let the user enter a positive integer

1) Determine whether the number is odd or even, and output the judging result

2) Determine if the number is a narcissus number and output the result (only 3 digits to consider)

Import Java.util.Scanner;

public class Problem2 {

public static void Main (string[] args) {

Scanner scan=new Scanner (system.in);

System.out.print ("Please enter a positive integer:");

int Num=scan.nextint ();

if (num<=0) {

System.out.println ("The number you entered is incorrect");

}else if (num%2==0) {

System.out.println ("The number is even");

}else{

System.out.println ("The number is odd");

}

int ge=num;

int SHI=NUM/10;

int bai=num/100;

if (num>=100&&num<1000&&ge*ge*ge+shi*shi*shi+bai*bai*bai==num) {

System.out.println ("The number is the number of daffodils");

}else if (num>=100&&num<1000&&ge*ge*ge+shi*shi*shi+bai*bai*bai!=num) {

System.out.println ("The number is not the number of daffodils");

}

//

for (int x=100;x<1000;x++) {

int ge=x;

int SHI=X/10;

int bai=x/100;

if (ge*ge*ge+shi*shi*shi+bai*bai*bai==x) {

SYSTEM.OUT.PRINTLN (x);

SYSTEM.OUT.PRINTLN (GE);

System.out.println (shi);

System.out.println (BAI);

//  }

//  }

}

}

3. Let the user enter a number, must be 1 to 7 (if the input is wrong, then the error), and then according to the number of user input to determine the day of the week (1: Monday, 2: Tuesday, ....., 7: Sunday. Requires judgment week using switch structure to complete)

Import Java.util.Scanner;

public class Problem3 {

public static void Main (string[] args) {

Scanner scan=new Scanner (system.in);

System.out.println ("Please enter Number (1-7)");

int Number=scan.nextint ();

Switch (number) {

Case 1:

System.out.println ("Monday");

Break

Case 2:

System.out.println ("Tuesday");

Break

Case 3:

System.out.println ("Wednesday");

Break

Case 4:

System.out.println ("Thursday");

Break

Case 5:

System.out.println ("Friday");

Break

Case 6:

System.out.println ("Saturday");

Break

Case 7:

System.out.println ("Sunday");

Break

Default:

System.out.println ("The number you entered is incorrect");

Break

}

}

5. Let the user enter a year (1900-2100, if not in this range, then prompt error), determine whether the year is a leap or common year.

Leap year rules: 4 Years A leap, a century does not leap; 400 years a leap.

Import Java.util.Scanner;

public class Problem5 {

public static void Main (string[] args) {

Scanner scan=new Scanner (system.in);

System.out.print ("Please enter a year (1900-2100):");

int Year=scan.nextint ();

if (year<1900| | YEAR>2100) {

SYSTEM.OUT.PRINTLN ("You entered the wrong year");

}else if (year>=1900&&year<=2100) {

if (year%4==0| | year0!=0) &&[email protected]==0) {

System.out.println (year+ "Years is a leap year");

}else{

SYSTEM.OUT.PRINTLN (year+ "Year is common year");

}

}

}

}

6. Let the user enter 3 numbers and then output in order from small to large.

Import Java.util.Scanner;

public class Problem6 {

public static void Main (string[] args) {

Scanner scan=new Scanner (system.in);

System.out.print ("Please enter three different numbers, \ n The first number:");

int Num1=scan.nextint ();

System.out.print ("second number:");

int Num2=scan.nextint ();

System.out.print ("Third number:");

int Num3=scan.nextint ();

int max=num1;

if (max>num2) {

if (max>num3) {

if (num2>num3) {

System.out.println (num3+ "," +num2+ "," +num1 ");

}else{

System.out.println (num2+ "," +num3+ "," +num1 ");

// }

}else{

System.out.println (num2+ "," +num1+ "," +num3 ");

//  }

}else if (max

max=num2;

if (max>num3) {

if (num1>num3) {

System.out.println (num3+ "," +num1+ "," +num2 ");

}else{

System.out.println (num1+ "," +num3+ "," +num2 ");

//             }

}else{

System.out.println (num1+ "," +num2+ "," +num3 ");

// }

// }

int temp;

if (num1>num2) {

temp=num2;

NUM2=NUM1;

Num1=temp;

}

if (num1>num3) {

TEMP=NUM3;

NUM3=NUM1;

Num1=temp;

}

if (num2>num3) {

TEMP=NUM3;

num3=num2;

Num2=temp;

}

System.out.println (num1+ "," +num2+ "," +num3 ");

}

}

7. Let the user enter a number between 1-9999 (if the input error, prompt error), reverse output the user input number.

Import Java.util.Scanner;

public class Problem7 {

public static void Main (string[] args) {

Scanner scan = new Scanner (system.in);

System.out.println ("Please enter a number of 1-9999");

int number = Scan.nextint ();

int GE = number% 10;

int shi = number/10% 10;

int bai = number/100% 10;

int qian = number/1000% 10;

if (number <= 0) {

SYSTEM.OUT.PRINTLN ("You entered the error");

} else if (number < 10) {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + ge);

} else if (number < 100) {

if (ge = = 0) {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + shi);

} else {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + ge + shi);

}

} else if (number < 1000) {

if (ge = = 0&&shi==0) {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" +bai);

} else if (ge==0) {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + Shi + bai);

}else{

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + ge + shi + bai);

}

} else if (number < 10000) {

if (ge = = 0&&shi==0&&bai==0) {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + qian);

} else if (ge==0&&shi==0) {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + Bai + Qian);

}else if (ge==0) {

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + Shi+bai + qian);

}else{

SYSTEM.OUT.PRINTLN ("Reverse output Result:" + Ge+shi+bai + qian);

}

} else {

SYSTEM.OUT.PRINTLN ("You entered the error");

}

}

}

8. Let the user enter a 5-digit number, determine whether it is a palindrome number, output judgment results.

Palindrome Number: If 12321 is a palindrome number, million is the same as the digit, 10 bits and thousands of the same.

Import Java.util.Scanner;

public class Problem8 {

public static void Main (string[] args) {

Scanner scan=new Scanner (system.in);

System.out.println ("Please enter a five-digit number");

int Num=scan.nextint ();

int ge=num;

int SHI=NUM/10;

int bai=num/100;

int qian=num/1000;

int wan=num/10000;

if (num<10000| | num>=100000) {

System.out.println ("The number you entered is incorrect");

}else{

if (Ge==wan&&shi==qian) {

System.out.println ("The number is a palindrome number");

}else{

System.out.println ("The number is not a palindrome number");

}

}

}

}

10. The bonus awarded by the Enterprise is based on the profit percentage. Profit (I) less than or equal to $100,000, the bonus can be raised by 10%, the profit is higher than $100,000, less than $200,000, less than 100,000 of the portion of the 10% commission, higher than the portion of 100,000 yuan, Cocoa Commission 7.5%, 200,000 to 400,000, higher than 200,000 yuan of the portion, can commission 5% ; Between 400,000 and 600,000 is higher than the portion of 400,000 yuan, can commission 3%, 600,000 to 1 million, higher than 600,000 yuan portion, can commission 1.5%, higher than 1 million yuan, the portion of more than 1 million yuan by 1% Commission, from the keyboard input month profit I, the total bonus should be issued?

Import Java.util.Scanner;

public class PROBLEM10 {

public static void Main (string[] args) {

Scanner scan=new Scanner (system.in);

System.out.println ("Please enter profit I (unit: million)");

int I=scan.nextint ();

Double bonus,bonus10,bonus20,bonus40,bonus60,bonus100,bonusout100;

bonus10=10*0.1;

bonus20=bonus10+10*0.075;

bonus40=bonus20+20*0.05;

bonus60=bonus40+20*0.03;

bonus100=bonus60+40*0.015;

if (i*10000<=100000) {

bonus=i*0.1;

SYSTEM.OUT.PRINTLN ("Total bonus payable:" +bonus+ "million");

}else if (i*10000<=200000) {

bonus=bonus10+ (I-10) *0.075;

SYSTEM.OUT.PRINTLN ("Total bonus payable:" +bonus+ "million");

}else if (i*10000<=400000) {

bonus=bonus20+ (I-20) *0.05;

SYSTEM.OUT.PRINTLN ("Total bonus payable:" +bonus+ "million");

}else if (i*10000<=600000) {

bonus=bonus40+ (I-40) *0.03;

SYSTEM.OUT.PRINTLN ("Total bonus payable:" +bonus+ "million");

}else if (i*10000<=1000000) {

bonus=bonus60+ (I-60) *0.015;

SYSTEM.OUT.PRINTLN ("Total bonus payable:" +bonus+ "million");

}else{

bonus=bonus100+ (I-100) *0.01;

SYSTEM.OUT.PRINTLN ("Total bonus payable:" +bonus+ "million");

}

}

}

Java Fundamentals 03

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.