Java high-precision binary conversions

POJ1131

Since the subject is only a fractional part (the whole number is 0), it is only possible to write the conversion method after the conversion of the binary.

8 Binary Conversion 10 binary method is, take 0.75 as an example, should be 7*8^-1 + 5*8^-2. So, you can directly locate the decimal place, and use this method to calculate.

1 ImportJava.util.*;2 Importjava.math.*;3 4  Public classMain5 {6      Public Static voidMain (String []args)7     {8Scanner cin =NewScanner (system.in);9 BigDecimal ans, t, TMP;Ten          while(Cin.hasnext ()) One         { AString st =Cin.nextline ();  -t = bigdecimal.valueof (1); -Ans = bigdecimal.valueof (0); the             intI, STA = St.indexof ('. '));  -              for(i = sta + 1; i < st.length (); i + +)) -             { -TMP = bigdecimal.valueof (St.charat (i)-' 0 '); +t = t.divide (NewBigDecimal ("8")); -TMP =tmp.multiply (t); +Ans =Ans.add (TMP); A             } atSystem.out.println (st+ "[8] =" +ans+ "[10]"); -         } -     } -}

Java high-precision binary conversions