Java Note 2

How to support soap

Download soap and decompress it to the corresponding directory,
Install Apache
The soap procedure is as follows:

1. Download the related configuration web server: (Tomcat is used as the Web server here)

Apache SOAP requires Apache xerces (Java) version 1.1.2 or later. It supports dom (Document Object Model) level.
2. namespace is supported. To download xerces-j-bin.1.2.0.zip to the apachewebsite, use the xercesfor version 1.2. Http://xml.apache.org/dist/xerces-j)
This file is an XML analyzer. Because the library or jar attached to the server is not used, you need to add it to classpath.
If you put xerces. jar into classpath, the Java code running in Tomcat may also find the wrong interface, because
In the shell script/batch command file that starts tomcat, xerces. jar is placed at the end of classpath.

Edit tomcat. bat in the Jakarta-Tomcat/bin directory and put xerces. jar in front of classpath.
 
Modifications made in the Jakarta-Tomcat/bin/tomcat. BAT file:

Set classpath = E:/xerces-1_2_0/xerces. jar; % classpath %; % CP %

The configuration of soap. jar is directly added to the classpath and path in the environment variable. The method is handled by j2sdk.

2. configure settings in the Web Server

For non-Tomcat servers, ie can access http: // localhost: 8080/soap /,
 
Extract the soap directory from the soap subdirectory.

If you use the Tomcat server as the configuration, there are two ways to configure it:

1. Use the context snippet
Methods: it seems that this method is not feasible (in doubt) in my experiments ),
Add a new one in the/CONF/server. xml configuration file of Tomcat.

Mark as follows:

Docbase = "E:/soap-2_0/webapps/soap" DEBUG = "1" Reloadable = "true">

In the docbase attribute of the context element, it is the directory for installing soap.

2. Directly copy the war file in the soap directory to the webapp directory of Tomcat and run http: // localhost: 8080/soap/
You can.

 

Start Tomcat and run startup. bat
Disable Tomcat and run shutdown. bat