Linux Learning Summary (66) a script that prints a bunch of numbers

Write a shell script that prompts for a paused number and then prints from 1 to that number. Then ask if you want to continue. Continue to enter a number and then print, or exit the script.
For example: If the input is 5, print 1 2 3 4 5, then continue to enter 10, and then print 6 7 8 9 101 times and so on.

Topic Analysis:
1. Prompt for user input, with read-p
2. To make a judgment on the user's input, whether it is a pure number. If not, give a hint and exit directly.
3 after the first printing results, if the user continues to enter the number, at this time not only to determine whether the user input is a pure number, but also to determine whether the number is larger than the first input.
4 to continue entering a number, you need to add a while loop to the second operation.
The overall framework is

judge（） {  判断输入的数字是否为纯数字}read -p  “输入一个数字” number1judge $number1for 循环依次打印出结果while :;doread -p "是否继续输入数字？ (yes or no）" a   case $a inyes)read  -p "请输入您想要暂停的数字（要大于$number1):" number2judege $number2if 判断number2 是否大于number1，大于循环打印结果，不然退出最后把number2 赋值给number1no)*)done

The complete code is

#!/bin/bashjudge_number()    //判断数字是否为纯数字{if [ -z "$1" ];then    echo "你必须输入一个数。"    exitfin=`echo $1|sed ‘s/[0-9]//g‘`if [ -n "$n" ];then    echo "你输入的数字有误"    exitfi}read -p  "请输入你想要暂停的数字：" number1judge_number $number1for i in `seq 1 $number1`;do    echo $idonewhile :;doread -p "是否继续输入数字？（输入yes或者no）" acase $a in    yes|YES)    read -p "请继续输入您想要暂停的数字（要大于$number1):" number2    judge_number $number2    if [ $number2 -le $number1 ];then        echo "请输入一个比$number1大的数字。"        exit    fi    number3=$[$mumber1+1]    for h in `seq $number3 $number2`;do        echo $h    done    number1=$number2    ;;    no|NO)    exit    ;;    *)    echo "请输入yes或者no"    exit    ;;esacdone

Linux Learning Summary (66) a script that prints a bunch of numbers