Linux Shell Programming---Calculate the first 10 large files in a specific directory

calculate the front of a specific directory Ten a large file

In a given directory, want to know which large files exist, take the top 10, by file size ranking

(1) , using awk to achieve

#!/bin/bash

Path=/root/shell

Find $path-type F | awk ' {

Var=$0

"Ls-l" var |getline var1

Split (Var1,a, "")

FILENAME=A[9]

FILESIZE=A[5]

printf ("%s%s\n", filename,filesize) | "Sort-k2-n-r|head-10"

}

‘

The above notation can cause memory overflow when there are more files.

Improve as follows:

#!/bin/bash

Path=/root/shell

Echo >r2.txt

Find $path-type F | awk ' {

Var=$0

"Ls-l" var |getline var1

Split (Var1,a, "")

FILENAME=A[9]

FILESIZE=A[5]

printf ("%s%s\n", filename,filesize)

}

' >r2.txt

Cat R2.txt|sort-k2-n-r | Head-10

(2) , using while to achieve

#!/bin/bash

Path=/root/shell

Echo >r1.txt

Find $path-type F|while Read line

Do

Filename= ' ls-l $line |awk ' {print $9} '

Filesize= ' ls-l $line |awk ' {print $} '

echo $filename $filesize >>r1.txt

Done

Cat R1.txt|sort-k2-n-r | Head-10

This article is from the "operation and maintenance of micro-letter" blog, please be sure to keep this source http://weixiaoxin.blog.51cto.com/13270051/1964074

Linux Shell Programming---Calculate the first 10 large files in a specific directory