Methods for listing in No2.python

First, the index

1 li = ["trony""shi""nvshen"  "nanshen"]2 li = li[0]3  Print(LI)4 >>>trony

IndexSecond, slicing

1 #List Index "Gu Tou regardless of tail"2Li = ["Trony","Shi","Nvshen","Nanshen"]3L1 = Li[0:2]4 Print(L1)5>>>["Trony","Shi"]6L2 = Li[0:-1]7 Print(L2)8>>>['Trony','Shi','Nvshen']9 #returns a list with a step size of 1TenL3 = [0:3:1] One Print(L3) A>>>['Trony','Shi','Nvshen']

slicesThird, increase

1Li = ["Trony","Shi","Nvshen","Nanshen"]2 #Append at end3Li.append ("Tiger")4 Print(LI)5>>>['Trony','Shi','Nvshen','Nanshen','Tiger']6 #inserting insert (index, value)7Li.insert (3,"Tiger")8 Print(LI)9>>>['Trony','Shi','Nvshen','Tiger','Nanshen']Ten #the Add extend () parameter of the iteration must be an iterative object OneLi.extend ("Monkey") A Print(LI) ->>>['Trony','Shi','Nvshen','Nanshen','m','o','N','k','y'] -Li.extend ([1, 2, 3]) the Print(LI) ->>>['Trony','Shi','Nvshen','Nanshen', 1, 2, 3]

IncreaseIv. deletion of

1Li = ["Trony","Shi","Nvshen","Nanshen"]2 #pop () is deleted by index, the deleted element is returned, and the last element is deleted by default without parameters and returned3Name = Li.pop (1)4 Print(name)5>>>Shi6 #Remove () Delete by element7Li.remove ("Trony")8 Print(LI)9>>>["Shi","Nvshen","Nanshen"]Ten #Clear One li.clear () A Print(LI) ->>>[] - #Delete List the delLi - #Slice Delete - delLi[0:2] - Print(LI) +>>>['Nvshen','Nanshen']

DeleteV. Change

1Li = ["Trony","Shi","Nvshen","Nanshen"]2 #Change by index3Li[0] ="Tiger"4 Print(LI)5>>>["Tiger","Shi","Nvshen","Nanshen"]6 #According to Slice change, first take out slice position, after iteration join7Li[0:3] = [1, 2, 3, 4]8 Print(LI)9>>>[1, 2, 3, 4,'Nanshen']

ChangeSix, check

1Li = ["Trony","Shi","Nvshen","Nanshen"]2 #use a circular check3  forIinchLi:4     Print(i)5>>>Trony6>>>Shi7>>>Nvshen8>>>Nanshen9 #Slice CheckTen Print(Li[0:2]) One>>>['Trony','Shi']

CheckVii. Public methods

1Li = ["Trony","Shi","Nvshen","Nanshen"]2 #Len () returns the length of the list3L =Len (LI)4 Print(L)5>>>46 7 #count () returns the number of occurrences of an element8num = Li.count ("Trony")9 Print(num)Ten>>>1 One  A #Sort -Num_list = [2, 1, 4, 8, 3, 5] - #forward Sort the Num_list.sort () - Print(num_list) ->>>[1, 2, 3, 4, 5, 8] - #Flashback Sort +Num_list.sort (reverse=True) - Print(num_list) +>>>[8, 5, 4, 3, 2, 1] A  at #reversal - Num_list.reverse () - Print(num_list) ->>>[5, 3, 8, 4, 1, 2]

Public Methods

Methods for listing in No2.python