# Python Exercise Exercises (chapater 5--python core programming)

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#!/usr/bin/env python
# Coding:utf-8
' For practise in Chapater five '

#定义一个函数, calculates and returns the two-digit flight
def product (A, B):
Return (A * b)

#根据分数输出同学的评分成绩 (A-F)
DEF score (i):
if (i > +) & (I < 100):
Return (' A ')
Elif (i >) & (I < 89):
Return (' B ')
Elif (i >) & (I < 79):
Return (' C ')
Elif (i >) & (I < 69):
Return (' D ')
Else
Return (' F ')
#print (Score (88))

#-----Practice to take the remainder-----

#1. Determine whether the year is a leap years
def estimate_leap (j): #j is the year
if ((j%4 = = 0) and (j%100! = 0)) or (j%400 = = 0):
Print ("%d is a leap year."%j)
Else
Print ("%d is a isn't leap year."%j)
Return
#print (Estimate_leap (1997))

#2. Take an amount that is less than \$1, and then calculate the minimum number of coins that can be exchanged. Coins have 1,5,10,25 cents
def coin (k): #k is the amount less than \$1
coin25 = Int (k/0.25)
coin10 = Int ((k-coin25*0.25)/0.1)
coin5 = Int ((k-coin25*0.25-coin10*0.1)/0.05)
coin1 = Int ((k-coin25*0.25-coin10*0.1) *100)
Return ("%.2f cent can change to at least%d coins."% (k, (coin25+coin10+coin5+coin1)))
#print (Coin (0.87))

#3.1 Use loops and arithmetic operations to find all the even numbers between 0-20
Def even_num (): #even number
For I in range (21):
If I% 2 = = 0:
Print (i),
#even_num ()

#3.2 use loops and arithmetic operations to find all odd
def odd_num ():  #odd number (uneven number)
for i in range:
if I% 2 = = 1:
print (i),
#odd_num ()

#3.3 Write a function, Detects whether an integer can be divisible by another integer. Ask the user to enter two numbers first, and then your function to determine whether
#     has an integer relationship, and returns True and False according to the result of the Judgment
Def Exact_divi (A, b):  # Detects if integer a can be divisible by integer b, b/a
if b% A = = 0:
print ('%d can is divisible by%d '% (a, b))
retur n True
else:
print ('%d can\ ' t is divisible by%d '% (a, b))
return False
#a = in T (Raw_input (' first number> '))
#b = Int (raw_input (' Second number> ')
#exact_divi (A, b)

#-----Arithmetic-----
#1. A calculator program with two operands and an operator: N1 operator N2. (unfinished)
def calculate (L): #l is an expression: N1 operator N2
NUM1 = float (L.split (") )
num2 = float (L.split (") )
Opert = L.split (") 
# return (NUM1 Opert num2)
#print (Calculate (' 11.2-2.9 ')) #这个题目还没解决

#2. Convert and write a pair of functions to convert degrees Fahrenheit to Celsius. The conversion formula is C = (F-32) * (5/9)
Def Centi_fahren (a): #参数a为华氏度, the return value of this function is Celsius.
Return ('%.2f '% ((a-32) * (float (5)/9)))

#print (Centi_fahren (100))

#3. System limitations. Write a script to confirm the range of integers, long integers, floating-point numbers, and complex numbers that your python can handle.
Import Sys
Def num_limit ():
Print (' The limit for int:%d%d '% (-sys.maxint-1, sys.maxint))
Print (' The limit for float:%e%e '% (sys.float_info, sys.float_info))
Print (' The limit for long:%s '% (Sys.long_info))
#num_limit ()

#4. Conversion. Write a function that converts the time represented by hours and minutes to a time that is expressed in minutes only.
def minutes (str):
Hours = Int (Str.split (': ') )
minutes = Int (str.split (': ') )
Minutes_all = hours * + minutes
Return Minutes_all
#print (minutes (' 12:50 '))

#5. Bank interest. Write a function that takes the term deposit interest rate as a parameter, assuming that the account calculates compound interest on a daily basis, calculate and return the annual return.
#工商银行定期存日款率0.35%
def interest_year_return (capital, rates): #capital is the principal, rate is the day
Capital_ori = Capital
i = 1
While True:
Capital = Capital * (1+rate) # capital = Capital * ((1+rate) **365)
i + = 1
if i = = 366:
Break
Return ((Capital-capital_ori)/capital_ori)
#print (Interest_year_return (10000, 0.000035))

#6. Greatest common divisor and least common multiple. Please calculate the greatest common divisor and least common multiple of two integers.
Def max_com_divisor (A, B): #整数a和b的最大公约数, using the Euclidean method (algorithm of division)
If A/b = = 0:
A, B = B, a
Algorithm_lst = [A, b]
i = 0
While True:
Algorithm_lst.append (Algorithm_lst[i]% algorithm_lst[i+1])
If algorithm_lst[i+2] = = 0:
return algorithm_lst[i+1]
Break
Else
i + = 1
#print Max_com_divisor (66, 242)
Def least_com_multiple (A, B): #整数a和b的最小公倍数, also using the Euclidean method (algorithm of division)
If A/b = = 0:
A, B = B, a
Algorithm_lst = [A, b]
i = 0
While True:
Algorithm_lst.append (Algorithm_lst[i]% algorithm_lst[i+1])
If algorithm_lst[i+2] = = 0:
Break
Else
i + = 1
LCM = (A * b)/algorithm_lst[i+1]
Return (LCM)
#print Least_com_multiple (12, 33)

Python Exercise Exercises (chapater 5--python core programming)

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