"Ebola" Python day3

Look back on yesterday's question

1, the user input 3 times, and realize the number of times to show the remaining

1i =02  whileI < 3:3Username = input ('Please enter user name:')4Password = input ('Please enter your password:')5     ifUsername = ='YH'  andPassword = ='mm':6         Print(Login successful)7     Else:8A = 2-I9         Print('Password re-entered incorrectly')Ten         Print('You also have the%s chance remaining'%(a)) Onei + = 1

User Login

2, Calculate 1-2+3-4+5-6 ... 99, and so on, remove the value of 88

1 #first write how to implement the complete plus and minus chain, according to the analysis can be obtained odd is plus even minus2sum = 13Count =04 #If you want to get 99, you have to set the relative conditions.5  whileCount < 100:6 #Use the IF condition to separate odd, even7     ifCount = = 88:8Count + = 19         ContinueTen     ifcount%2 = =0: OneSum-=Count A     Else: -Sum + =Count -Count + = 1 the Print(sum)

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int type

int is commonly used to convert other forms into numbers, and other forms of attention must be digital

The int contains the common 1,2,3,4,5 +-*%////

Common forms are converted from characters to numbers

Str converted toint Data Conversion

Boolean type (BOOL)

1. The bool type has only two forms of False ture

2, False is 0 ture is 1

convert bool type to int

Yes, if 0 is false, not 0 is ture.

1 i = 42 b = bool (i)3print(i)45 >>> 1

bool Value Conversion

STR converted to BOOL type

s = "" False

s = ' 0 ' Ture

Non-null characters are ture

String str

Index and slice of a string

1, in Python is starting with 0 as the first bit

Gu Tou Regardless of the end of the slicing method

 1  a = ' abcdefghigklmn '  2  print  (A[0:3]) #  Span style= "COLOR: #008000" > Prints the No. 0 to the second bit abc,0 can not write  3  print  (a[:]) #   print out as ABCDEFGHIGKLMN  4  print  (a[1:-3]) #  bcdefghigk  5  Span style= "COLOR: #0000ff" >print  (a[5:1]) #   reverse intercept FEDCB  6  print  (A[-1:1:2]) #   reverse intercept with a step of 2 nlghfd  

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Common ways of string editing

1A ='gaojian12*'2A1 = A.capitalise ()#Initial capital Letter gaojian12*3A2 = A.upper ()#All caps gaojian12*4A3 = A.lower ()#All lowercase gaojian12*5 " "6 about all uppercase all lowercase issues are often applied to system assurance case- insensitive7 s_str = ' acEQ3 '8 you_input = input ("Please enter a verification code, not case sensitive")9 if s_str.upper () = = You_input.upper ():Ten print (' input succeeded ') One Else: A print (' Please re-enter ') - " " -a4 = a.swapcase ()#Case Flip theAA ='Gao Jian Tao' -A5 = aa.title ()#the first letter of each word is capitalized, the difference is the space Gao Jian Tao -A6 = A.center (20,'@')#Length 20 fills both sides with @, and center @ can also be a space @@@@@[email protected]@@@@ -A7 = A.count ('a', 0,9)#The number of occurrences of an element in a string, the number of times a slice query a appears print (A7) <<< 2 +Aa1 ="wwho\t" -A8 = Aa1.expandtabs ()#put \ t before the completion of a tab 8 key print (A8) ' wwho ' If the preceding characters are more than 8 to 16 characters +A9 = A.startswith ('Ian', 4,7)#returns a Boolean value in 第4-7位 to determine whether the print (A9) begins with Ian Ture AA10 = A.endswith ('Ian', 4,7)#returns a Boolean value for print (A10) at 第4-7位 to determine whether to end with Ian Ture atA11 = A.find ('Ian'1,6)#in 1,6 to find whether the element in the string exists, if it can find the return position, cannot find return-1 print (A11) returns 4 -A12 = A.index ('Ian', 1,6)#An error has been found in the presence of the element 1,6 for the search string -A13 = A.split ('a')Print(A13)#[' G ', ' Oji ', ' n12* '] in what division, and eventually form a list this list does not contain this split element.  - #ret91 = ' title,tilte,atre, '. Rsplit (' t ', 1) starts from the right to the first T, and does not contain a list of T-splits - #print (ret91) [' Title,tilte,a ', ' re, '] -Name='*egon**' in Print(Name.strip ('*'))#Delete the * number on both sides can also be replaced with spaces, letters and other things - Print(Name.lstrip ('*'))#Delete the * number on the left to Print(Name.rstrip ('*'))#Delete the * number on the right + #format three gameplay formats output -res='{} {} {}'. Format ('Egon', 18,'male') theres='{1} {0} {1}'. Format ('Egon', 18,'male') *res='{name} {age} {sex}'. Format (sex='male', name='Egon', age=18) $ #ReplacePanax NotoginsengName='Gao Say:i has one tesla,my name is Gao' - Print(Name.replace ('Gao','Gaojiantao', 1))#replace the old ' Gao ' for Gaojiantao replacement number 1 the #Gaojiantao Say:i has one tesla,my name is Gao + ##is系列 AName ='gaojiantaoshuai123' the Print(Name.isalnum ())#The string is made up of letters or numbers, and the returned value is Tuer + Print(Name.isalpha ())#The string consists only of letters False - Print(Name.isdigit ())#string only consists of numbers False

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Tuple Tupe

1. Cannot be changed or modified or sliced

2, Ganso with (4, ' Huju ', (' Ju ', ' yh ')) said

Lists List

1. Use [] to express

Dictionary

1, with the key to the expression

For syntax

1  forIinchRange (1,10):2     Print(i)3 4  forIinchRange (1,10,2):#Step Size5     Print(i)6 7  forIinchRange (10,1,-2):#Reverse Step8     Print(i)

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"Ebola" Python day3