Shell batch rename objects by date

In the case of a lot of service logs or a lot of scattered files that need to be sorted together in batches, the shell script can be quickly used to solve the problem:

 
Date = $ (date + % Y _ % m _ % d-% H % m % s); find *-type F | while read file; do MV $ File $ {file }. $ {date}; done
 

The preceding statement can quickly find all files in the directory and rename them.

How can I find the file with the specified suffix and rename it? For better understandingCodeSeparate execution:

 

 
Find./log-name"*. Log"|WhileRead FileDoDate= $ (Date + % Y % m % d _ % H % m % S _ %N) mV $ file./Temp_log/$ {Date}. logdone
 

 

The first line of the statement: Find all files under the current log directory with the suffix *. log.

Statement of the third line: import the current time variable into the date variable (generate a random number ).

Row 4 Statement: Move and rename the searched file.

Next we will explain the date variable:

% Y year

% M month

% D Date

% H hour

% M minutes

% S seconds

% S get the timestamp, current to: seconds between 00:00:00

% N: obtain the data in the current time, accurate to one second in

Therefore, we can see that the output of the date = $ (date + % Y % m % d _ % H % m % S _ % N) variable is basically a random number, it is difficult for % N to show the same result during CPU execution. In this way, the file will not be overwritten during renaming.

There is also a system variable $ random for the generation of random numbers:

For example, input echo $ random on the terminal.

Return Value: 26885

We can also perform MD5 encryption for it: Echo $ random | md5sum

Returned value: 5ebc600b4d19e86719a491d7dd365880