Shell finishing (===date) small script for command

(a) accept an input, judging is not a date, the user's input can be 2017-10-1 or 2017.10.1 or 2017/10/1

The shell code is as follows

#!/bin/bash

Read-p "Input:" Date

A= ' echo $date | Awk-f ' [./-] ' {print $ '/' $ '/' $ $} '

Date-d $a &>/dev/null

If [$?-eq 0];then

echo "OK"

Else

echo "No"

Fi

(ii) write the date into a text that determines the date of the year, respectively.

For example

[email protected] ding1]# cat File1

2017-10-1

2016-2-2

2017-1-1

[Email protected] ding1]#

The shell code is as follows

Str () {

# a= ' echo $line | TR '/.-'/'

A= ' echo $line | Awk-f "[./-]" ' {print $ "/" $ "/" $ $} "

Date-d $a +%j

}

#set-X

Cat File1 | While Read line

Do

Str

Done

#set +x

Summary of the simple date command:

Date-d < string >: Displays the date and time referred to by the self-character string. String before and after the double quotation marks, as if some do not add, specific case analysis

For example:

[Email protected] ding1]# date-d 2017-1-1 +%j #加%j indicates the day ordinal of the year

001

[Email protected] ding1]# date-d +%j

Date: Invalid Day "+%j"

[Email protected] ding1]#

In other words, a string must be specified after date-d.

[Email protected] ding1]# date-d 2017-1-1 #显示字符串所指的时间与日期

January 01, 2017 Sunday 00:00:00 CST

[Email protected] ding1]#

Date +%f Displays the current time, (year-month-day), for example:

[Email protected] ding1]# date +%f

2017-10-05

[Email protected] ding1]#

+%f is equivalent to +%y-%m-%d

For example:

[Email protected] ding1]# date +%y-%m-%d

17-10-05

[Email protected] ding1]# date +%y*%m*%d #中间的符号自己定义

17*10*05

[Email protected] ding1]#

For example I want to show the next month and the next year today

[Email protected]lhost ding1]# date-d +1month +%y-%m-%d

17-11-05

[Email protected] ding1]# date-d +1year +%f

2018-10-05

[Email protected] ding1]#

Date-s < string;: Sets the date and time according to the string, only the root permission can be set, the other can only be viewed. Double quotation marks around strings

[[Email protected] ding1]# Date

Thursday, October 05, 2017 10:21:52 CST

[[email protected] ding1]# date-s 2012-5-23 01:01:10

Date: Parameter ' 01:01:10 ' lacks a leading "+";

When the option is used to describe the date, any non-option parameter must appear as a "+"-guided string

Try executing "date--help" for more information.

[Email protected] ding1]# date-s "2012-5-23 01:01:10" #这个地方加上双引号

Wednesday, May 23, 2012 01:01:10 CST

[[Email protected] ding1]# Date

Wednesday, May 23, 2012 01:01:13 CST

[Email protected] ding1]#

This article is from the "It Life" blog, so be sure to keep this source http://dingxue.blog.51cto.com/12290895/1970420

Shell finishing (===date) small script for command