Shell scripts determine if a leap year

Source: Internet
Author: User

#! /bin/bashecho-n Input year to judge if it was a leap year:read yearlet "y1= $year% 4" let "y2= $year%" let "y3= $year% 4 XX "If [! "$y 1"-eq 0]thenleap=0elif [! "$y 2"-eq 0]thenleap=1elif ["$y 3"-eq 0]thenleap=1elseleap=0fiif ["$leap"-eq 1]thenecho "$year is a leap year" ELSEEC Ho "$year is not a leap year" fi

  

[Email protected] desktop]#./ifrunnian.sh Input year to judge if it's a leap year:20032003 is not a leap year[[email PR Otected] desktop]#./ifrunnian.sh Input year to judge if it was a leap year:20052005 is not a leap year[[email protected] D esktop]#./ifrunnian.sh Input year to judge if it is a leap year:20082008 are a leap year

  

Shell scripts determine if a leap year

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