The shell script implementation finds the last occurrence of a character in a string _linux shell

You need to find the last position of one of the characters in the string, which is available in PHP (Strrpos) or Perl (Rindex), and you can't think of a way out of the shell. Post on the Forum also no one answer (do not know whether the problem is too simple or really very advanced ...) ）。

Because the matter is not urgent, so help college students. Pacman is worthy of a master, 32 next to wake up in the dream of people:

Rindex.sh Code:

Copy Code code as follows:

#!/bin/bash

strtocheck=$1;
chartosearch=$2;

Let pos= ' echo ' $strToCheck | Awk-f ' $charToSearch ' ' {printf '%d ', Length ($)-length ($NF)} '

echo "Char $charToSearch Lastpos is: $pos"

Use examples:

Copy Code code as follows:

[zeal]$ sh rindex.sh www.zeali.net.
Char. Lastpos is:10

Calfen provides a more self-reliant way: He wrote a small program in C to achieve rindex function, gcc rindex.c-o rindex after the shell has a can be invoked rindex:)
RINDEX.C Code:

Copy Code code as follows:

#include <strings.h>
int main (int argc, char *argv[]) {
char* Wholeword;
Char Subchar;
char* Subword;

int ret;

if (argc!=3) {
printf ("Use:rindex word char\n");
Exit (0);
}
WHOLEWORD=ARGV[1];
SUBCHAR=*ARGV[2];
Subword=rindex (Wholeword,subchar);

if (0 = subword)
ret = 0;
Else
ret = (subword-wholeword+1);
printf ("%d\n", ret);
}