c# java interop

solution:tree=[] # @param {listnode[]} lists # @return {ListNode} def mergeklists (self, lists): Length=len (lists) if Length==0:return None elif Length==1:return lists[0] self.tree=[0 for i I N range (length)] Self.inittree (lists,length) if Lists[self.tree[1]]==none:return None p=lists[self.tr EE[1]] Lists[self.tree[1]]=lists[self.tree[1]].next head=p self.adjusttoroot (lists, (Self.tree[1]+leng TH)/2,length) while Lists[self.tree[1]]!=none:p.next=lists[self.tree[1]] lists[self.tree[1] =lists

Vim is a powerful editor and may be more complex to configure on-line gods. There are many functions. My configuration here will meet the basic requirements. Fast and versatile, as long as you open your own VIMRC files follow my add a few lines of code can be resolved.Let's look directly at my configuration file. Let's talk about how Ubuntu and redhat open configuration file VIMRC* under the RedhatFirst switch to root. And then entervim /etc/vimrcunder UbuntuDirect inputsudo vim /etc/vim/vi

Ava: data is stored in large-end byte order. [the data is stored at a high address, the data is stored at a low address, and the data is stored at a high level before the array] Windows (intel Platform): data is stored in a small byte order. [low-level data is stored at a low address, and high-level data is stored at a high address, high data is stored behind the array] (windows receives the short sent by java, int needs to call ntohs and ntohl to con

JAVA tool-convert java's String class to a char * array in C In JNI development, there is usually a conversion of String and char * When java interacts with c Code. However, note that these two types are not the same.I found a tool method as a memo. Char * Jstring2CStr (JNIEnv * env, jstring jstr) {char * rtn = NULL;

problem-solving ideas: such as solution, Time complexity O (n) Java source code (spents 373ms):public class Solution {public int maxarea (int[] height) { int max=-1,l=0,r=height.length-1; while (lC Language Source code (spents 12ms):int Maxarea (int* height, int heightsize) { int max=-1,area,l=0,r=heightsize-1,k; while (lC + + source code (spents 30ms):Class Solution {public: int Maxarea (vectorPython source code (spents 152

findsubstring ( Self, S, words): Lens=len (s); Lenw=len (Words[0]); Length=len (words) map={};res=[] for i in range (length): if words[i] in map:map[words[i]]+=1 else:map[words[i]]=1 if not words[i] in S:return res for I in range (lens-lenw*length+1): tmp={};j=0;flag=true for J in range (length): pos=i+j*lenw Sub=s[pos:pos +LENW] if sub in map: num=0

(spents 48ms):/** * Return An array of arrays of size *returnsize. * Note:the returned array must is malloced, assume caller calls free (). */void QuickSort (int* nums,int first,int end) {int temp,l,r; if (first>=end) return; Temp=nums[first]; L=first;r=end; while (LC + + source code (66MS):Class Solution {public:vectorPython source code (407MS):Class solution: # @param {integer[]} nums # @return {integer[][]} def threesum (self, nums): res = [] Length=

(int x) { int flag=x>0?1:-1,res=0; x=x>0?x:-x; while (x>0) { if (res*10.0 + x%10 > 2147483647) return 0; res = res*10+x%10; x/=10; } return res*flag;} }C Language Source code (spents 10ms):int reverse (int x) { int flag=x>0?1:-1,res=0; x=x>0?x:-x; while (x>0) { if ((2147483647.0-x%10)/10C + + source code (spents 13ms):Class Solution {public: int reverse (int x)

;next=p->next->next; } return head; };Python source code (67MS):# Definition for singly-linked list.# class listnode:# def __init__ (self, x): # self.val = x# Self.next = Nonec Lass Solution: # @param {ListNode} head # @param {integer} n # @return {listnode} def removenthfromend ( Self, head, N): s=head;p=listnode (0) P.next=head while n>0 and S!=none: n-=1;s=s.next While S!=none: s=s.next;p=p.next

JavaPackage Com.example.aric.test;import Javax.crypto.cipher;import Javax.crypto.secretkey;import Javax.crypto.secretkeyfactory;import Javax.crypto.spec.deskeyspec;import Javax.crypto.spec.IvParameterSpec; Import Android.util.base64;public class DES {public final static string des_key_string = "Absujsuu";p ublic static string E Ncrypt (String message, String key) throws Exception {Cipher Cipher = cipher.getinstance ("des/cbc/pkcs5padding");D Eskeyspec Deskeyspec = new Deskeyspec (key.getbytes (

1. Define members in the interfaceC #, I added a field N to interface ITest, then vs directly shows the red bottom line, and the error is that the interface cannot contain fieldsJava, for example, the compilation is also an error but not the interface can not be included but the assignment is missing, then we will be assigned to look at the value. You can see that there is no problem, that is, the member variable defaults to public static final, we know that final must be assigned, so no assignm

Brief Introduction gSOAP is a soap/xml-C + + language-bound tool that can be used to quickly and easily develop Soap/xml server-side and client. Because gSOAP has fairly good compatibility, through gSOAP, we can invoke SOAP services developed in languages such as Java,. Net, Delhpi, PHP, or provide soap services to them. 1 2 See the following address for specific processes:http://panxq0809.iteye.com/blo

This is the second article about android multithread in c/c ++ to call JNI. First Article address: http://blog.csdn.net/wu4long/article/details/17756419 As mentioned above, the third method of android isClassLoaderObject. Cache a reference toClassLoaderObject somewhere handy, and issueloadClassCILS directly. This requires some effort.What should I do? (This requires some effort )?Below I will be specific

: vectorPython source code (spents 69ms):Class Solution: map=["", "", "abc", "Def", "Ghi", "JKL", "MnO", "PQRS", "TUV", "WXYZ"] length=0;res=[] # @par am {string} digits # @return {string[]} def lettercombinations (self, digits): Self.length=len (digits) self.res=[] if Self.length==0:return self.res; Tmp=[' For I in Range (self.length)] self.getlettercom (0,digits,tmp) return self.res def getlettercom ( SELF,INDEX,DIGITS,TMP):

=2147483647; Private final static int int_min=-2147483648; public int myatoi (String str) {char[] chs = Str.tochararray (); int index=0; while (IndexC Language Source code (spents 5ms):int Myatoi (char* str) { int flag=1,res=0,dig; while (*str== ') str++; if (*str== '-') { flag=-1; str++; } else if (*str== ' + ') { str++; } while (*STR) { if (*strC + + source code (spents 17ms):Class Solution {public: int myatoi (string str

Directly on the steps:Writing Java code Package cn.ace.jni; Public class testnative { Public native void SayHello (); Public Static void Main (string[] args) {}} Use the Javah.exe tool to generate a header file cn_ace_jni_testnative.hBuild Method:Execute the following command: Testnative is the name of the classGenerate File Contents: /* Don't EDIT this file-it are machine generated */#include /* Header for

If the following if statement is availableProgramWill it be compiled? Int X, Y = 10If (x = y) x = y; I have verified that C and C ++ can be compiled but cannot be compiled in Java, the reason is that a Boolean value must be returned for the condition expression in the brackets of the IF statement. The C language co

Problem:Write a function to find the longest common prefix string amongst an array of strings.Solution:time complexity O (n)Main topic:give a string array to find the maximum prefix common substring of these strings. Problem Solving Ideas:since it is a common substring, that each string must contain, and in the head, first the first string as the default maximum, and then followed by each string in contrast, calculate all the maximum matching length, the smallest is the lengthJava source code (s

Solvesudoku (vectorPython source code (636MS):Class Solution: # @param {character[][]} board # @return {void} do not return anything, modify board In-place Instea D. def solvesudoku (self, Board): self. SudoKu (board,0,0) def SudoKu (self,board,i,j): If I==8 and J==9:return True if j==9:i+=1;j=0 if boa Rd[i][j]!= '. ': if self. SudoKu (board,i,j+1): Return True Else:map=self.getvalidnum (board,i,j) for K in range (1,10): If MAP[K]==0:BOARD[I][J]=CHR (K+ord (' 0 ')) if self.

-point method to determine the position of the elements, the exact sort of the back when there is no need for a great move, so to achieve high efficiency. For example: for a[] ={63, 4, 24, 1, 3, 15}, first we use the start step steps =length/2=3 each element in the array, and so on, exchange, that is to say, a[0] compared to a[0+step=3, a[0]>a[3] swap position, A [0]=1,a[3]=63 (in this case, 1 jumped to the first place), and then proceed to the next group of comparison A[1]>a[4] (subscript are d