funny ladder

Bestcoder Round #90At least three knowledge points exploded at this time ....A. ZZ questionPress Test instructions copy init function and then count OKB.The game problem does not understand the half-day of the SG ..... The result of this question ....CData structure problem I wrote for half an hour and found that the color was changed .... Oh, my God, deep-fried.D.I don't know what to do with the topic ... The official puzzle is to kill the little circle.Bestcoder Round #90//div All-in-one roll-

President Barack Obama has not only called on everyone to learn to program, or even to lead by example, to become the first president in American history to write computer code. At the end of 2014, to celebrate the official launch of computer Science Week, Obama wrote a very simple computer code: Draw a square on the screen. Now you draw with him, too!Input format:The input gives the square edge length N (3Output format:Outputs a square drawn by a given character C. But notice that the row spaci

][ -];voidMake () { for(inti =1; I 0] = A[i]; ans[i][0] = i; } for(intj =1; (1 for(inti =1; i+ (111], dp[i+ (11))][j-1]);if(dp[i][j-1] = = Dp[i][j]) ans[i][j] = ans[i][j-1];ElseANS[I][J] = ans[i+ (11))][j-1]; } for(inti =1; I 1; for(inti =2; I if(a[i-1] 1]+1; for(inti = n1; I >=1; i--)if(a[i+1] 1]+1;} PII Query (intLintR) {intK = (int)((Log((r-l+1)*1.0))/Log(2.0));intMAXN;intTemp MAXN = Max (Dp[l][k], dp[r-(11][k]);if(MAXN = = Dp[l][k]) temp = ans[l][k];Elsetemp = ans[r-(11][K];returnMake_pair (

)) {Nextmap.get (NEWSTR). Add (CURSTR); if(Newstr.equals (start)) {found=true; Finallevel=Curlevel; Foundcurcycle=true; Break; } if(Visitedcurlevel.add (newstr)) {Queue.add (NewStringwithlevel (NEWSTR, Curlevel + 1)); } } } if(foundcurcycle) { Break; } Curstrchararray[i]=Originalchar; } } if(found) {ArrayListNewArraylist(); List.add (start); Getpaths (Start, End, list, Finallevel+ 1, Nextmap, res); } returnRes;}Private voidGetpa

#include #include#include#defineE 2.7182818DoubleFDoublex) { returnPow (e,-x*x);}DoubleCalc (DoubleADoubleBDoubleESP) { intDone0); intn=1; Doubleh,tn,t2n,k,temp,x; H=b-A; Tn=h* (f (a) +f (b))/2.0; while(!Done ) {Temp=0; for(k=0; k) {x=a+ (k +0.5)*h; Temp+=f (x); } t2n= (tn+h*temp)/2.0; if(Fabs (T2N-TN) 1; Else{Tn=t2n; N=n*2; H=h/2; } } returnt2n;}intMain () {printf ("%.50lf\n", Calc (-10000,10000, 1e- -)); return 0;} Code is not robust, pending modificationIntegral: Variable Step

Each PAT candidate will be assigned two seat numbers, one for the test seat and one for the test seat, when taking the exam. Under normal circumstances, candidates in the entrance of the first to obtain the seat number of the test machine, seated into the test machine status, the system will show the test seat number of the candidate, the test candidates need to change to the test seat seating. But some of the candidates are late, the test machine is over, they can only take the seat number of t

Enter an integer that prints the phonetic alphabet for each number. When the integer is negative, the word "fu" is first output. 10 numbers correspond to the following pinyin:0:ling1:yi2:er3:san4:si5:wu6:liu7:qi8:ba9:jiuInput format:The input gives an integer in a row, such as: 1234 .Tip: integers include negative numbers, 0, and positive numbers.Output format:In a row output this integer corresponding to the pinyin, each number of pinyin separated by a space, there is no last space at the end o

the stock (in million tonnes) of each mooncake, and the last line gives a positive n indicating the total price of each mooncake (in billions of dollars). The numbers are separated by a space.Output format:For each set of test cases, output the maximum profit in a row, in units of billions and accurate to 2 digits after the decimal point.Input Sample:3 2018 15 1075 72 45Sample output:94.50Simple structural and sequencing application questions1#include 2#include 3#include 4 using namespacestd;5

Title DescriptionDescriptionEnter n number, nEnter a descriptionInput DescriptionFirst line an integer nNext line n integers, each integer less than 231-1Output descriptionOutput DescriptionMinimum and maximum numberSample inputSample Input41 2 3 4Sample outputSample Output1 4Data range and TipsData Size HintNoIdea: This problem is relatively simple, you can put all the numbers into the array, and then a little use of the fast line can be finished, the output of the No. 0 and the first n-1The c

outputSample Output620Data range and TipsData Size HintThe original ticket price is greater than 100 less than 9999, the discount rate is greater than 1 less than 9.9.Idea: This problem is a bit complicated, you can save the ticket price and discount rate with two float floats, then calculate the product divided by 100 (why divide by 100, because to keep to 10 bits, if divided by 10 is only reserved to the bit, and then the result is returned to 10), you can use: = (int) (x+0.5 ) > (int) x? (i

Title Description: Given A and n, computes the A+AA+AAA+A...A (n a). Input: There are several groups of test data, input a,n (1 Output: For each set of inputs, output the results. Sample input: 1 10 Sample output: 1234567900The difficulty of this problem is to deal with a long, long number of sums 1#include 2#include 3

Some water problems.T1201:#include intmin=0x7fffffff, max=-0x7fffffff;intN,i,a;intMain () {scanf ("%d",n); for(i=1; i) {scanf ("%d",a);if(A>max) max=A;if(aA;} printf ("%d%d\n", Min,max);}View CodeT1202:#include intsum=0;intN,i,a;intMain () {scanf ("%d",n); for(i=1; i) {scanf ("%d",a); Sum+=A;} printf ("%d\n", sum);}View CodeT1203:#include #includeusing namespacestd;Const Doublee=1e-8;intMain () {DoubleA, b;cin>> a >>b;if((a-e"Yes";Elsecout"No";}View CodeT1206:#include double A; int Main () {sca

. If you can return the distance. If it is not possible to determine whether the string after the change of a character in DiC, then add to the que, que with "" "empty string separation, before we do level order is null because the que is the root node, where the string is stored, so with the null character. Encounter null character if que is already empty then you can return 0, if not empty, then push the null character to represent another layer.classSolution { Public:intLadderlength (stringSt

start end and, we know we is done. This link provides a nice two-end search solution.1 classSolution {2 Public:3 intLadderlength (stringBeginword,stringEndword, unordered_setstring>worddict) {4 Worddict.insert (Endword);5queuestring>tovisit;6 addnextwords (Beginword, Worddict, tovisit);7 intDist =2;8 while(!Tovisit.empty ()) {9 intnum =tovisit.size ();Ten for(inti =0; i ) { One stringWord =Tovisit.front (); A Tovisit.pop (); -

assign values by yourself, but it is quite understandable. First, assign a diagonal value (core, core), and forward and down along the diagonal lines to the upper and lower directions. You can write several matrix examples. n is the upper right corner of the maximum even number, and N is the lower left corner of the maximum odd number. N is required to be an odd number. The upper triangle matrix is based on the upper right corner (Up, Up) value. It is easy to write each column-1 to the righ

the Newword has a parent node and the current number of layers is greater than its minimum number of layers, it is marked as accessed Else{Visited.insert (Newword); } } } } } returnsequences; } InlinevoidAddsequence (unordered_mapstring, pairstring,int> > father,stringStartstringEndstringword) {Vectorstring>sequence; if(Word! =end) Sequence.push_back (word); Sequence.push_back (end);

The shortest distance is required. Use Dijkstra to find the shortest path between nodes. Note: If the two elements in the enumerated dictionary can be converted, the time-out will occur. Improvement: For each string, to enumerate the values of each character, it is necessary to enumerate N x 26 times for a string with a length of N. If it is just a simple enumeration, the duplicate edge will appear: For example, ABC, BBC, and CBC. After a graph is created, each two nodes have two bidirectional e

Recently want to study in detail the elevator scheduling algorithm, but the content involved too much, there is no time. About the types of elevator algorithms:Http://www.cnblogs.com/jianyungsun/archive/2011/03/16/1986439.htmlThen I can only look at the simple.This is a topic in the beauty of programming:A total of 6 elevators are in a building. At rush hour, everyone on each floor is up and down, and the elevator stops on each floor.Interns are often very impatient with the elevators that stop

#include ExercisesFirst consider adding a layer in the current situation, then we can enumerate the last step length to get the answer.Finally, the number of Cattleya is obtained.Code:F=[0]*60f[1]=1n=int (Raw_input ()) for I in Range (2,n+1): f[i]=f[i-1]* (4*i-2)/(i+1) print (F[n])"BZOJ2822" "AHOI2012" Tree house ladder Cattleya number Python high precision

); (3) Iterator Erase (const_iterator first, const_iterator last); 5. If the current string gets end after changing a letter, the conversion ends. Returns PATH+1. End and start do not need to be inside the dictionary. This is the termination condition of the BFS search.if (str = = end) return path + 1; If the changed word equals end returns path+1Complexity: The worst case scenario is to look at all strings of length l, or the strings in the diction