glasslab 303

=, max=) Checks whether the annotated value lies between (inclusive) the specified minimum and maximum. in@Range (min=10000,max=50000,message= "Range.bean.wage") - PrivateBigDecimal wage; to + The @Valid recursively verifies the associated object, and if the associated object is a collection or an array, the element is recursively checked, and if it is a map, the value part of it is verified. (whether recursive validation is performed) - @CreditCardNumber credit card verification the @Email Ve

@Null: Limit can only be Null@NotNull: Limit must be non-null@AssertFalse: The limit must be false@AssertTrue: The limit must be true@DecimalMax (value): Limit must be a number that is less than the specified value@DecimalMin (value): The limit must be a number that is not less than the specified value@Digits (integer,fraction): The limit must be a decimal, and the number of digits in the integer portion cannot exceed integer, and the number of fractional digits cannot exceed fraction@Future: Th

}) Public@interface IsMobile {//Allow empty PropertiesBoolean required ()default true; //If the checksum does not pass the returned prompt informationString message ()default "cell phone number format error"; Classdefault { }; Classdefault { };}2.3. CalibratorImport Javax.validation.constraintvalidator;import Javax.validation.constraintvalidatorcontext;import Org.apache.commons.lang3.stringutils;import Com.imooc.miaosha.util.ValidatorUtil; //ismobile: Custom Annotations//String: annotation para

Codeforces Round #303 (Div. 2) One question + four greedy ones .... Codeforces Round #303 (Div. 2) A. Toy Cars time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Susie, thanks to her older brother, likes to play with cars. Today she decided to set up a tournament between them. The process of a tournament is described in the next paragraph. T

/** 303. Range Sum query-immutable * 2016-7-3 by Mingyang * This topic is very simple at first, it is good to accumulate directly, but it is said that Sumrange will be called many times * therefore need to save the results first, the call can be directly returned The The first consideration is to use DP[I][J] to directly store the and of the elements between I and J, * but the memory exceeds the limit. Then consider using Dp[i] to store 0 to I element

Codeforces Round #303 (Div. 2) A. Simple question /*************************************** * *********************************> File Name: a. cpp> Author: ALex> Mail: zchao1995@gmail.com> Created Time: wednesday ******************************** **************************************** /# include # Include # Include # Include # Include # Include # Include # Inclu

Similarity vs. 27 binary conversions #include #include#include#includestring>#include#include#includeusing namespacestd;intMain () {intT; strings; CIN>>T; while(t--) {cin>>s; if(s[0] >='A') { intres =0; intLen =s.length (); for(intI=0; i) {res= res* -+s[i]-'A'+1; } coutEndl; } Else { stringRes; intn =atoi (S.c_str ()); while(n) {if(n% -==0) {res+='Z'; N-= -; } ElseRes+ = n% -+'A'-1; N/= -; } reverse (Res.begin (), Res.end ()); coutEndl; } }

Topic:Given an integer array nums, find the sum of the elements between indices I and J (i ≤ J), inclusive.Example:Given nums = [-2, 0, 3, -5, 2, -1]sumrange (0, 2), 1sumRange (2, 5), -1sumrange (0, 5), 3Note: Assume that the array does is not a change. There is many calls to sumrange function. Your Numarray object would be instantiated and called as such:Numarray Numarray (nums);Numarray.sumrange (0, 1);Numarray.sumrange (1, 2);Ideas:The solution of all sumrange (0, I) is obta

); } }puts("");}intMain () {intN, M, I, J, u, V; LL W, ans; while(scanf("%d%d", n,m)!=eof) {memset(head,-1,sizeof(head)); Cnt=0; for(i=1; i1e16; } for(i=1; iscanf("%d%d%i64d", u,v,w); Add (U,V,W); Add (V,U,W); }scanf("%d", u); SPFA (U);memset(Ha,0,sizeof(ha)); ans=0; for(i=1; i for(j=head[i];j!=-1; j=edge[j].next) {intV =EDGE[J].V;if(D[i]+edge[j].w==d[v]) {fei[tot].u=i;

The problem was caught in the cards. Card for one hours, too true.Test instructions and analysis (Codeforces 545C)Test instructions: given \ (n\) tree, in \ (x\) position, high to \ (h\), then can be left to pour right down, and then down will occupy \ ([x-h,x]\) or \ ([x,x+h]\ ) interval, if not felled, occupies \ ([x,x]\) area.Ask you how many trees you cut down, the condition is that after the fall of the occupied zone can not be occupied by other trees.Analysis: Under the condition of this t

A. Toy Cars Little Susie, thanks to his older brother, likes to play with cars. Today she decided to set up a tournament between them. The process of a tournament is described in the next paragraph. There is n toy cars. Each pair collides. The

Serial Number InterchangeTime limit: Ms | Memory limit: 65535 KB Difficulty: 2 description Dr.kong designed a smart robot, which will quickly calculate cell coordinates in a spreadsheet. The row coordinates of a cell are numeric ordinal numbers

Question: Returns the maximum abscissa of light. Note that the light may overlap with the pipe It can also go through the Turning Point Solution: Enumerate whether each light can pass the cross section (Line Segment) at each turning point     // Big

Air Check @Null Verify that the object is Null @NotNull Verify that the object is not null and cannot search for a string of length 0 @NotBlank Check that the constraint string is null and that the length of the trim is greater than 0, only for

Common nsarray Methods 1. Create an array object and use the initialization method or constructor. Running result: 19:29:06. 750 oc07 _ container class [5676: 303] ( "\ U738b \ u6668 ", "\ U5218 \ u56fd \ u4f1f ", "\ U90d1 \ u6d77 \ u5764" ) ( "\ U674e \ u667a ", "\ U9b4f \ u5927 \ u536b ", "\ U5218 \ u5929 \ u4f1f" ) ( "\ U738b \ u6668 ", "\ U5218 \ u56fd \ u4f1f ", "\ U90d1 \ u6d77 \ u5764" ) 2. Obtain the number of elements. 3. Obtain the obj

First, the basic concept of copying objectsCopy an object as a copy and open up a new piece of memory to store the replica object.Second, if an object wants to have the function of copying, must implement NSObject's Common objects are: NSNumber, NSString, Nsarray, Nsdictionary, Nsmutablearray, Nsmutabledictionay, NSMutableString, Copy-generated object is immutable, mutablecopy the resulting object when the variableThird, the difference between retain and copy @autoreleasepool { Nsmutab

1. Basic concepts of copying objects Copy an object as a copy and open up a new memory to store the copy object. 2. To copy an object Protocols and Protocol Common NSObject objects include NSNumber, NSString, NSArray, NSDictionary, NSMutableArray, NSMutableDictionay, and NSMutableString. objects generated by copy cannot be changed. objects generated by mutableCopy can be changed. Third, the difference between retain and copy @autoreleasepool { NSMutableArray *array=[

Common nsset Methods The set is similar to a jar. Once the object is "thrown into" nsset set, there is no obvious order between multiple objects in the set. nsset uses the hash algorithm to store elements in the set, so it has good access and search performance. 1. Create a collection object. The nsset set cannot contain the same elements. Two identical elements are put in, and only one element can be saved in the result. Running result: 09:00:16. 615 oc07 _ set [520:

In the 3rd chapter of the HTTP authoritative guide, when explaining the 30X status code, it is completely unclear why there should be 302, 303, 307, and their relationship, a "problem in HTTP/1/1" Let me confused, inexplicable. So I've collected this resource on the Internet, mark.First, status code--302RFC1945 (http://tools.ietf.org/html/rfc1945#page-34), That is, HTTP1.0, when introducing 302, said that if the client sends a POST request and receive

operate inside the main function. For example:#import First of all, we have three bookmarks: Baidu, Sina and Sohu. The content of the bookmark is the contents of the program.We then verify that adding bookmarks, finding bookmarks, deleting bookmarks, sorting bookmarks, and modifying bookmarks are the correct way to behave.The output of the final program is:2015-07-22 20:15:58.560 3. Bookmark Manager [3,083:303] Repeat add 2015-07-22 20:15:58.562 3. B