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Math Olympic Question answer: Goal 2017 Junior Maths League training Team homework answer-1

$, and the $BE is intercepted on $AB $ = bc$, which proves that the target is $AE = ad$.by $A, B, C, d$ four points round and tangent properties of $$\angle{bec} = \angle{bce} = {1\over2} (180^\circ-\angle{ebc}) = {1\OVER2}\ANGLE{ADC} = \angl e{odc},$$ therefore $O, E, C, d$ Four points are all round. This can be $$\angle{aed} = \angle{ocd} = {1\over 2}\angle{bcd} = {1\over2} (180^\circ-\angle{a}), $$ is proof $ae = ad$.Q.E.D.7, the two circles with each other in the $D $, the line cut a round

2016 APE Tutoring Junior High School Math contest training Camp homework answer-8

^3 = a^2 + b^2+ c^2 = A+b+c = 1$, then $abc =? $Answer:by $ $a ^3 + b^3 + c^3-3abc = (A + B + C) (a^2 + b^2 + c^2-ab-bc-ca) $$ and $$ (A + B + c) ^2-(a^2 + b^2 + c^2) = 0$$ $$\ RightArrow 1-3ABC = 1-(ab + BC + CA) = 1\rightarrow ABC = 0.$$5. If $2a = 6b = 3c$, and $ab + BC + CA = 99$, then $2a^2 + 12b^2 + 9c^2 =? $ Answer: $$\begin{cases}a = 3b\\ c = 2b \end{cases} \rightarrow 3b^2 + 2b^2 + 6b^2 = \rightarrow b^2 = 9.$ $ so $$2a^2 + 12b^2 + 9c^2 = 18b

2016 APE Tutoring Junior High School Math contest training Camp homework answer-7

) + (2x^2-7x + 6) = 3x^2-4x + 2$, so consider swapping elements.Make $x ^2 + 3x-4 = m$, $2x^2-7x + 6 = n$, then $ $m ^2 + n^2 = (m + N) ^2 \rightarrow mn = 0.$$ This can be $ $x ^2 + 3x-4 = 0\rightar Row (x+4) (x-1) = 0 \rightarrow x_1 = -4,\ x_2 = 1,$$ or $$2x^2-7x + 6 = 0 \rightarrow (2x-3) (x-2) = 0 \rightarrow x _3 = {3\over2},\ X_4 = 2.$$ fully, the solution of the original equation is: $ $x _1 = -4,\ x_2 = 1,\ x_3 = {3\over2},\ X_4 = 2.$$5. Set $x + y = 1$, $x ^2 + y^2 = 2$, $x ^7 + y^7$ v

2016 APE Tutoring Junior High School Math contest training Camp homework answer-13

. $$ (+ x) \cdot \frac{7}{10} = \times \frac{3}{5} + x$$ $$\rightarrow x = \frac{200}{3}.$$ so should be added copper $\d frac{200}{3}$ G.4. Hard aluminum is $4\%$ copper, $1\%$ manganese, $0.5\%$ magnesium and $94.5\%$ aluminum preparation, melting loss rate according to $1.5\%$ calculation. Manufacturing $250$ kg hard aluminum, how many kilograms of the above materials? (Keep one decimal place)Answer:The total amount of raw materials required for the establishment is $x $. $$\rightarrow X\cdot

Marco 2016 new Linux+python high-end operation third week homework answer

/maxusers.txt[[emailprotected]~]# cat/tmp/maxusers.txtlibstoragemgmt:x:992:990:daemonaccountfor libstoragemgmt:/var/run/lsm:/sbin/nologinnBsp;saslauth:x:993:76:saslauthduser:/run/saslauthd:/sbin/nologingeoclue:x : 994:991:userforgeoclue:/var/lib/geoclue:/sbin/nologincolord:x:995:993: userforcolord:/var/lib/colord:/sbin/nologinunbound:x:996:994:unbound dnsresolver:/etc/unbound:/sbin/nologinpolkitd:x:997:996:userfor Polkitd:/:/sbin/nologinsystemd-network:x:998:997:systemdnetworkmanagement :/:/sbin

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