kaspersky internet security 2018 system requirements
kaspersky internet security 2018 system requirements
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enable the compiled executable document to be debugged with GDB
New exploit.c, code below, \x?? \x?? \x?? \x?? Need to add shellcode to the address stored in memory because the location can overwrite the return address just after an overflow occurs.
We want to get shellcode in-memory address, enter commands gdb stack anddisass main
According to strcpy(buffer + 100,shellcode) the statement, we calculate shellcode the address as0xffffd350(十六进制) + 0x64(100的十六进制) = 0xffffd3b4(十六进制)
Mo
lower layer. Due to locality, writing back can significantly reduce bus traffic.The disadvantage is increased complexity.Another problem is how to deal with write Miss.Write allocation: load the corresponding lower-level block to the cache, and then update the cache block. The disadvantage is that each Miss will cause a block to be transferred from the lower layer to the cache.Non-write allocation: Avoid high-speed caching and write the word directly to the lower layer.Performance impact of hig
exploit.c file to compile.6. Running the programAfter the address protection mechanism has been modified, the run is unsuccessful and the segment error is displayed.
Experimental HarvestFeel according to the steps of the experiment step by step, really can get the corresponding results, but the whole experiment is a walk a process, or do not understand the relevant memory overflow of the specific process, as well as the relevant attack ideas, their level or not standards, there is a long way
20165214 2018-2017-1 "Information Security system Design Fundamentals" The third week study summary of learning Contents1. In fact, the GCC command invokes a series of programs that convert the source code into executable code.2, the actual realization of the memory system is to combine multiple hardware memory and ope
2018-2019 20165203 Information Security System Design Basics Chapter 5 study summary teaching material content summary important concepts
Storage System: a hierarchy of storage devices with different capacity costs and access time.
Cache memory ------ buffer area for data and instructions in primary storage ------ d
1. Machine-Level Code(1) Two kinds of abstract
Defines the format and behavior of machine-level programs by ISA
The memory address used by the machine-level program is the virtual address
2. Data format3. Operand designator4. Press in and eject stack data
Follow the principle of first in and out
Push Press in, pop delete
Pushq press four words into the stack popq four words pop-up stack
5. Arithmetic and logical operations
LEAQ Load Valid address
INC plus a
D
non-gate or non-gate
HCL integer Expression
Case Expression Format:
[ select 1: expr 1 select 2: expr 2 . select k: expr k ]
Set Relationship:iexp in{ iexp1,iexp2,...iexpk }
Arithmetic/logic unit (ALU)
Sequential implementation of Y86-64
Organize the processing into stages
Value fetch--> decoding decode--> performing execute--> memory--> writeback write back write back--> update PC update
SEQ
week's exam error summary 1.The following jump commands are related to ZF ()A. jmpB. JeC. jsD. JaE. JBF. JbeAnalytical:2.Assuming that the function of the C-expression T=a+b is completed with the add instruction, the correct statement about the condition Code Register is ()A. If t==0, then zf=1B. If tC. If tD. if (aE. if (aF. LEAQ directive does not affect the condition code registerG. CMP directives do not affect the condition code registerAnalysis: Textbook p135ZF: 0 logo. The result of the r
I. Learning Objectives
Understanding the role of ISA abstraction
Master Isa, and be able to learn other architecture extrapolate
Understanding the pipeline and how it is implemented
Second, the Learning content y86-64 directive
MOVQ directive IRMOVQ rrmovq mrmovq RMMOVQ
Four integer manipulation instructions Addq,subq,andq,xorq only the Register data
7 Jump Instructions Cmovle cmovl cmove cmovne cmovge CMOVG
The call command returns the address to the stack, and then j
1.Y86-64 Instruction Set architecture①Y86-64 directive
MOVQ directive IRMOVQ rrmovq mrmovq RMMOVQ
Four integer manipulation instructions Addq,subq,andq,xorq only the Register data
7 Jump Instructions Cmovle cmovl cmove cmovne cmovge CMOVG
The call command returns the address to the stack, and then jumps to the destination address, and the RET instruction returns from such calls
Pushq and POPQ instructions are implemented into the stack and out of the stack
Execution of Halt
2018-2019-1 20165228 "Fundamentals of Information Security system design" the third week of learning summary of the Learning Content Summary program machine-level representation: Two important abstractions of computer systems
ISA (Instruction set architecture): Instruction set architecture, machine-level program format and behavior. Defines the format of
2018-2019-1 20165336 "Information Security system Design Fundamentals" Fourth week study summary 1. The knowledge points learned in the textbook
The states that are visible to programmers (assembler programmers, compilers, and so on) in y86-64 include program registers, condition codes, program states, program counters (PCS), memory
Y86-64 15 Program regist
2018-2019 20165219 Summary of storage technology in week 5 of Information Security System Design Basics Random Access Memory: Comparison of SRAM and DRAM, traditional DRAM and enhanced dram Enhanced DRAM: Fast page mode DRAM: allows continuous access to the same row to get services directly from the row buffer. Extended Data Output DRAM: Allows CAS signals to
2018-2019-1 20165228 "The foundation of Information security system design" The second week study summary textbook learning content Summary information = bit + context
Unsigned encoding: Represents a number greater than or equal to zero based on the traditional binary notation
Complement coding: represents the most common way to sign a certificate, a number
2018-2019-1 20165329 "Information Security system Design Fundamentals" 4th Week Study SummarySummary of learning contents of textbook
Y86-64 directive: The y86-64 instruction is a subset of the x86-84 instruction set. It includes only 8-byte integer operations. There are 4 integer operations directives: ADDQ, SUBQ, ANDQ, and Xorq. There are 7 jump commands: j
2018-2019 20165227 "Information Security system Design Fundamentals" The third week to learn to summarize learning objectives
Understanding the concept of reverse
Master X86 compilation base, able to read (reverse) Assembly code
Understanding ISA (Instruction set architecture)
Understand the concept of function call stack frames and can debug
-2018-2019-1 20165206 "basis of information security system design" weekly learning Summary-textbook learning content Summary-hexadecimal conversion and bitwise calculation:
Converts a hexadecimal parameter to a binary representation and performs binary operations.
And, or, not, or, in bitwise operations, corresponds to , |, ~ in C ,~ ^-Logical operation:
Only 0
2018-2019-1 20165314 summary of the fifth week of Information Security System Design Basics
SRAM and DRAM are both easy to lose, but they have different structures, different speeds, and faster access speed.
The prom can only be programmed once.
Programs stored in ROM devices are usually called firmware.
The EEPROM can erase the information on the chip with
2018-2019-1 20165333 "Information Security system Design Fundamentals" Third Week study summarySummary of learning contents of textbookThe machine-level representation of the program:Two important abstractions of computer systemsISA (Instruction set architecture): Instruction set architecture, machine-level program format and behavior. Defines the format of the p
selection: determine where the desired word starts in the block.
Associated High-speed cache:1. group selection in group-connected high-speed cache: Same as group selection in direct ing high-speed cache, group index bit Identification Group.2. Row matching and word selection in the group-connected high-speed cache: each group is considered as a small memory associated with a (Key, value) pair array,3. Input key to return the value in the corresponding array. The cache must search for each row
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