calculate distance between two coordinates latitude longitude

Original link: Calculate distance according to two-point latitude and longitudeHow are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is a center of the north-south poles and the Earth.Imaginary line), in the Earth's waist draw a large circle perpendicular to the axis, so

Calculate distance based on two-point latitude and longitudeHow are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is a center of the north-south poles and the Earth.Imaginary line), in the Earth's waist draw a large circle perpendicular to the axis, so that each point on

* * @param LNG * @param lat * @return */public int[] Getxy (double LNG, double lat) {///compare with reference points longitude calculate coordinates if (LNG > D34[0]) {return getXY1 (LNG, LAT);} else {return getXY2 (LNG, LAT);}} /** * The fixed point is the baseline xy coordinate */private int[] getXY1 (double LNG, double lat) {//WillLatitude converted to Gauss

This article is the process of converting a shapfile file without latitude and longitude coordinates to the correct spherical coordinates.Using the tool: ArcMap 10Step one, ArcMap add the Shapfile file (shp to convert)Step two, set the projection coordinates①Ii③④⑤⑥Step three, set the projection①Ii③④⑤Note: TIF files are

How does JavaScript calculate the distance between two places? I believe there are many ways to achieve this, the next article will introduce you to JavaScript through latitude and longitude to calculate the distance between the t

1 functiontobdmap (x, y) {2 varX_PI = 3.14159265358979324 * 3000.0/180.0;3 varz = MATH.SQRT (x * x + y * y) + 0.00002 * Math.sin (Y *x_pi);4 vartheta = math.atan2 (y, x) + 0.000003 * MATH.COS (x *x_pi);5 varBd_lon = Z * Math.Cos (theta) + 0.0065;6 varBd_lat = Z * Math.sin (theta) + 0.006;7 varPT =NewBmap.point (Bd_lon, Bd_lat);8 returnpt;9}Code Description: The map