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Turn How are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is an imaginary line through both the north and the South Poles and the center of the Earth), and the Earth's waist draws a large circle perpendicular to its axis, so that every point on the circle is equal to the north and South poles, and this circle is called "the equator". At the north and south sides of the equator, many circles parallel to the equator are drawn, that is, "weft ring
poles and the Earth's Center), draw a large circle perpendicular to the Earth's axis in the waist, so that every point in the circle is equal to the distance between the north and south poles. This circle is called the "Equator ". On the north and south sides of the Equator, draw many circles parallel to the equator, which are "latitude circles". The line segments that constitute these circles are called weft wires. We set the equator to zero
How are these longitude determined? The earth is constantly spinning around its axis (the earth's axis is a center of the north-south poles and the Earth.Imaginary line), in the Earth's waist draw a large circle perpendicular to the axis, so that each point on the circle and the North and south poles of the same distance, this circleIt is called "the equator". At the north and south sides of the equator, many circles parallel to the equator are drawn, which are the "weft rings", the segments tha
HTML5 provides access to the geographical location of the API, it is convenient to determine the latitude and longitude of customers, we have access to latitude and longitude, you can provide the API through the Baidu map to determine the location of the user. At present, the computer is sometimes not available, the phone is still very good, in addition, to obtain the location is not very accurate, but u
PHP Code: Reprint http://www.cnblogs.com/caichenghui/p/5977431.html1 /**2 * Find the distance between two known longitude and latitude, in meters3 * 4 * @param lng1 $, lng2 longitude5 * @param lat1 $, lat2 latitude6 * @return float distance, Unit meter7 * @author www.Alixixi.com8 */9 functionGetdistance ($LNG 1,$lat 1,$LNG 2,$lat 2) {Ten //turn angle into Fox degree One $radLat 1=Deg2rad($lat 1);//the Deg2rad () function converts an angle to
Latitude algorithm $pi80 = m_pi/180; $lat 1=34.7465763; $lng 1=113.65778739999996; $lat 2=34.684795; $LNG 2=112.43594499999995; $lat 1 *= $pi; $LNG 1 *= $pi; $lat 2 *= $pi; $LNG 2 *= $pi; $r = 6372.797; Mean radius of Earth in miles $dlat = $lat 2-$lat 1; $DLNG = $lng 2-$LNG 1; $a = sin ($dlat/2) *sin ($dlat/2) +cos ($lat 1) *cos ($lat 2) *sin ($DLNG/2) *sin ($DLNG/2); $c = 2 * atan2 (sqrt ($a), sqrt (1-$a)); $km =round ($r * $c, 2);//return
First, ordinary IP is unable to obtain detailed latitude and longitude, only through network services to obtain The most useful in China is the JavaScript API provided by www.ip-look-up.com, as long as the following statements are written in the Web page He's going to return a JSON data in memory, just a little bit. iplocation = {' Latitude ': 39.9289, ' longitude ': 116.388, ' address ': {' city ': ' Be
Label:The world's 78,707 major cities information MySQL database, including latitude and longitude coordinate values, has been exported to the SQL file, because it is relatively large, there is 10M, so this is exported separately, for the upgrade failed to manually import students,This data is mainly used for weather forecast plug-in, the weather report plug-in, need to first from the library, query the city's ID, in the ID passed to the interface, re
By latitude, the database is compared stringbuffer SB = new StringBuffer () sb.append ("Select TimeKey,") Sb.append ("ROUND (6378.138*2*asin ( SQRT (POW (Sin (*pi ()/180-lat*pi ()/180)/2), 2), Sb.append (+cos (? *pi ()/180) *cos (Lat*pi ()/180) *pow (Sin ((? *pi ()/) ); Sb.append ("180-lng*pi ()/180)/2), 2)) *1000) as JL") Sb.append ("From T_news have JL Mysql takes a distance comparison between the specified lati
calculation distance principle of latitude and longitudeinterchange of latitude and longitudeDegree (DDD): E 108.90593 degrees N 34.2163 degreesHow to Degree (DDD):: 108.90593 degrees to the degree of seconds (DMS) Longitude e 108 degrees 54 minutes 22.2 seconds? The conversion method is to change 108.90593 integer digits to 108 (degrees), with 0.90593*60=54.3558 and integer digits of 54 (points), 0.3558*60
: = Z * cos (T) + 0.0065;EXCEPTIONWhen OTHERS ThenNULL;END;Test code:DeclareVal varchar2 (1024);Lat number;LNG number;BeginLat: = 25.123456;LNG: = 120.987654;Google2baidu (LAT,LNG);Val: = To_char (lat) | | ', ' | | To_char (LNG);Dbms_output.put_line (Val);Baidu2google (LAT,LNG);Val: = To_char (lat) | | ', ' | | To_char (LNG);Dbms_output.put_line (Val);EndOutput Result:25.12950357111129114394070387150607218949, 120.9941596847708026959269928710265389825.12345611379500842252418931941721965068, 120.
= 3.1415926;x = x/1000000.0;y = y-500000.0;BF = 9.04353692458*x-0.00001007623*pow (x,2.0) -0.00074438304*pow (x,3.0) -0.00000463064*pow (x,4.0) +0.00000505846* Pow (x,5.0) -0.00000016754*pow (x,6.0);HBF = BF * pi/180.0;SA = 6378245.0;SB = 6356863.019;SE2 = 0.006693421623;SEP2 = 0.006738525415;W1 = sin (HBF);W2 = 1.0-se2 * POW (W1, (double) 2);W = sqrt (w2);MF = sa* (1.0-SE2)/pow (W, (double) 3);W3 = cos (HBF);W4 = POW (SA, (double) 2) *pow (W3, (double) 2) + POW (SB, (double) 2) *pow (W1, (doub
Package com.maputil; Import Java.io.BufferedReader; Import java.io.IOException; Import Java.io.InputStream; Import Java.io.InputStreamReader; Import java.io.UnsupportedEncodingException; Import java.net.HttpURLConnection; Import Java.net.URL; Import java.net.URLConnection; Import java.util.ArrayList; Import Java.util.HashMap; Import java.util.List; Import Java.util.Map; Import Java.util.Map.Entry; public class Addresslatlngutil {private static final String Request_encode = "UTF-8"; private st
Recently used in accordance with the latitude and longitude calculation of the Earth's surface two distance between the formula, and then use JS to achieve a bit. There are probably two ways to calculate the distance between two points on the Earth's surface. The first is the default Earth is a smooth spherical surface, and then calculate the distance between any two points, this distance is called the Great Circle distance (the great Circle Distance)
Java known two locations latitude and longitude distance (very accurate) Package com.lbnet.lzx.util; public class GoogleMap {Private static final Double Earth_radius = 6378.137;private static Double rad (double D){return d * math.pi/180.0;}/*** ????}????????????? /γ???* @param LAT1* @param lng1* @param lat2* @param lng2* @return*/public static double Getdistance (double lat1, double lng1, double lat2, double lng2){Double RADLAT1 = rad (LAT1);Double
ctrl_ove = new Bmap.overviewmapcontrol ({anchor:bmap_anchor_bottom_right,isopen:1}); Map.addcontrol (ctrl_ove); Add a scale control to the map var Ctrl_sca = new Bmap.scalecontrol ({anchor:bmap_anchor_bottom_left}); Map.addcontrol (CTRL_SCA); } Second, click the location and then convert to address by latitude Listens for click event map.addeventlistener ("click", Function (e) { map.clearoverlays (); Alert (
Baidu Map, to achieve vehicle trajectory mapping Implementation ideas: 1. Vehicle trajectory mapping according to latitude and longitude 2. Using the Baidu Map API two overlay implementation, Polyline (polyline) Draw track, Marker (icon) to draw the car icon 3. Connect each of the two coordinates to form a coherent trajectory line 4. After the next icon is generated, delete the last drawn icon to create a car moving animation sense 5. This example use
data from the program9876543 9876543.12 9876540mysql> INSERT into T1 values (1.21, 1.12,1.21);1. In Toad for MySQL, the display isC1 C2 C31.21 1.12 1.212. The display in MySQL Query browser isC1 C2 C31.21 1.12 1.213. Remove data from the program1.21 1.12 1.21mysql> INSERT into T1 values (1.2, 1.2,1.2);1. In Toad for MySQL, the display isC1 C2 C31.2 1.20 1.22. The display in MySQL Query browser isC1 C2 C31.20 1.20 1.23. Remove data from the program1.2 1.20 1.2mysql> INSERT INTO T1 values (987654
1 DROP FUNCTION IF EXISTS ' getdistance ';2 DELIMITER;;3 CREATE FUNCTION ' getdistance ' (4Lon1 Float (10,7) 5, Lat1 float (10,7)6, Lon2 float (10,7) 7, Lat2 float (10,7)8 ) RETURNS Double9 beginTen declare d double; One declare radius int; ASet radius = 6378140; -Set D = (2*atan2 (SQRT (SIN (LAT1-LAT2) *pi ()/180/2) -*sin ((LAT1-LAT2) *pi ()/180/2) + theCOS (Lat2*pi ()/180) *cos (LAT1*PI ()/180) -*sin ((Lon1-lon2) *pi ()/180/2) -*sin ((Lon1-lon2) *pi ()/180/2)), -SQRT (1-sin (LAT1-
How can I obtain the longitude and latitude of my current location? After knowing the longitude and latitude of the two locations, how can we calculate the distance between the two locations? Recently I am working on a public account. I need to obtain the user's latitude and longitude, and then calculate the distance between the user's
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