python programming third edition

To create a TCP server pseudo-code:s = socket () #创建服务器套接字S.bind () #套接字与地址绑定S.listen () #监听连接Inf_loop: #服务器无限循环cs = s.accept () #接受客户端连接, if there is no connection, blockComm_loop: #通信循环CS.RECV ()/cs.send () #会话Cs.close () #关闭客户端套接字S.close () #关闭服务器套接字Here's the code:#!/usr/bin/envpython3#encoding:utf-8fromsocketimport*fromtime importctimehost= ' port=21567bufsize=1024addr= (HOST, port) Tcpsersock=socket (af_inet,sock_stream) tcpsersock.bind (ADDR) Tcpsersock.listen (5) while true:print (' wait

Afternoon brain Watt, thought for a while did not come up with algorithms, just convulsions finally realized, hereby recorded. ￣-￣| |Topic(a) Create a function with the name FINDCHR (), FINDCHR () to find the character char in string strings, find the index that returns the value, otherwise return-1.(b) Create another function called RFINDCHR (), looking for the character char last occurrence. It works like FINDCHR (), but it looks forward from the end of the string.(c) Create a third function,

Python core Programming (third edition), after-school problem solving, chapter two. All the answers are for bloggers to write their own, because the level is limited, welcome to put forward opinions, mutual exchanges. 2-1. What is the difference between a connection-oriented socket and a connectionless socket. Connection-oriented: Before communication, a connect

), Global Namespaces (Globals Namespaces), and built-in namespaces (Build-in namespaces).Build-in namespaces is first loaded into the active namespaces by the Python interpreter, which is made up of the names in the __buildins__ module.Global namespaces is then loaded as an active namespaces, and you can use the Globals () built-in function to determine whether a name belongs to the global namespace.Local namespaces when needed, that is, if a function

2-5 Loops and Numbersa) i = 0While I Print Ii + = 1b) for I in Range (0,11):Print I2-6 conditionalsN =int (raw_input (' Enter a number: '))If n print ' negative 'Elif n > 0:print ' positive 'Elseprint ' zero '2-7 Loops and stringss = Raw_input (' Enter a string: ')For Each_char in S:Print Each_charOrFor I in range (len (s)):Print I,s[i]Ori = 0Slen = Len (s)While I Print I,s[i]I +=1OrFor I,x in enumerate (s):Print I,x2-8 Loops and operatorsSubtot = 0For I in range (5):Subtot + = Int (raw_input ('

()Choice=input ("Please choice One:")If choice==1:Sum=sum ()Print "sum is%d"%sumElif choice==2:Ave=ave ()Print "average is%f"%aveElif choice== ' x ':BreakElsePrint "Wrong choice,please choose again!"2-15#让用户输入3个数值并将分别将他们保存到3个不同的变量中, do not use a list or sorting algorithm#从小到大While True:Num1=int (raw_input ("Please input NUM1:"))Num2=int (raw_input ("Please input num2:"))Num3=int (raw_input ("Please input num3:"))If num1>num2:Tmp=num1Num1=num2Num2=tmpIf num2>num3:Tmp=num2Num2=num3Num3=tmpIf num1

2.12.32.42.52.62.72.82.92.102.11deftest_sum (): Tup=("1","2","3","6","5") Sum=0 forIinchTup:sum=float (i) +sumreturnsumdeftest11 (): whiletrue:string=raw_input (">>") ifstring=="1": Sum=test_sum ()Print "sum:", Sumelifstring=="2": Sum=test_sum () Avg=sum/5Print"avg:", Avgelifstring=="x": Exit ()Else: Print"Please enter 1 or 2 or x"test11 ()2.12-2.132.15B:deftest15 (): Num1=raw_input ("First num:") num2=raw_input ("Second num:") num3=raw_input ("Third num:") NUM1=float (NUM1) nu

: Finally10-5. Exceptions. What exceptions will be thrown by the Python code snippet below these interaction interpreters (see the list of built-in exceptions given in Table 10.2):(a) >>>if 3 (b) >>>alist = [' Hello ', ' world ', ' anyone ', ' Home ']>>>print ' The last string of alist is: ', Alist[len (alist)](c) >>>x(d) >>>x = 4 0(e) >>>import Math>>>i = math.sqrt (-1)(a) Syntaxerror:invalid syntax (b) indexerror:list index out of range (c) nameerro

　　　　　　　　　　　　　　 numeric operation built-in function functions nbsp; function ABS (num) Returns the absolute value of num Coerce (NUM1, num2) The Converts NUM1 and num2 to the same type and then returns as a tuple. Divmod (NUM1, num2) Division-the combination of the take redundancy operation. Returns a tuple (Num1/num2,num1%num2). The quotient of floating-point

1 #coding:utf-8 # using Windows system, first line ' #!/usr/bin/env Pyton ' useless, all changed to ' # Coding:utf-8 '2 3 'readtextfile.py--Read and display text file'4 5 #get filename6fname = Raw_input ('Enter FileName:')7 Print8 9 #attempt to open file for readingTen Try: OneFobj = open (fname,'R') # Try to open fname A exceptIOError, E:#The detailed cause of the captured IOError error is placed in Object E, and then the except code block that runs the exception (can also be written

Note: I use the python3.5. where range and Xrange,input and Raw_input have been merged8-1. Conditional statements. Take a look at the following code:# statement AIf x > 0:# statement BPassElif x # statement CPassElse# statement DPass# statement E(a) If x(b) If x=0, which of the above statements will be executed?(c) If x>0, which of the above statements will be executed?(a) ACE, (b) ADE, (c) ABE8-2. cycle. Write a program that allows the user to enter 3 numbers: (f) ROM, (t) O and (i) ncrement. T

Java programming ideology fourth edition Chapter 3 personal exercises, programming ideology Fourth Edition I hope you will be grateful for your criticism ......)Chapter 3 exercise 9 (1) show the maximum and minimum numbers represented by float and double indexes respectively public class MaxMinFloatDouble {

C ++ programming ideology (second edition) Chapter 2nd object creation and use (exercises and answers), java programming ideology (second edition) Exercise-related code Hello. cpp Stream2.cpp Nomconv.cpp Fillvector.cpp 2-1 modify Hello. cpp so that he can print your name and age (or your shoes, dog's age, etc., as l

Author: Brian W. Kernighan/(Mei) Dennis M. RitchiePublishing house: Mechanical Industry PressSubtitle: 2nd edition • NewOriginal name: The C programming LanguageTranslator: Baowen Xu/li zhi/Yu Jinyuan revisionPublication year: 2004-1Number of pages: 258Price: 30.00 RMBBinding: Paperbackisbn:9787111128069Content profile ...In the history of computer development, no progr