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bit of attention, the dictionary ordering note the starting position of the same substring order, its order is the reverse of the enumeration order. In other words, we avoid falling into another hole when we are bypassing a pit.Finally, HBW mentions a method of optimizing the random string suffix array to O (n), and when the rank array has a maximum value of n, it simply break off, seemingly a simple and useful optimization#include #include#include#include#includeusing namespacestd;#defineMAXN

'; Ch=getchar ();}returnX*f;}CharSTR[MAXN];intNstructsa{intRANK[MAXN],SA[MAXN],TSA[MAXN],A[MAXN],B[MAXN];intCNTA[MAXN],CNTB[MAXN];intheight[maxn],best[maxn][ A],n;voidGetintnn) {n=nn; Rep (I,0,666) cnta[i]=0; Rep (I,1, n) cnta[str[i]]++; Rep (I,1,666) cnta[i]+=cnta[i-1]; Rrep (I,n,1) Sa[cnta[str[i]]--]=i; rank[sa[1]]=1; Rep (I,2, N) {if(Str[sa[i]]==str[sa[i-1]]) {Rank[sa[i]]=rank[sa[i-1]]; }Else{rank[sa[i]]=1+rank[sa[i-1]]; } } for(intL=1; ran

[MAXN],A[MAXN],B[MAXN]; intRANK[MAXN],SA[MAXN],TSA[MAXN],HT[MAXN]; voidsort () { for(inti =0; I -; i + +) cnta[i] =0; for(inti =1; I ; for(inti =1; I -; i + +) Cnta[i] + = cnta[i-1]; for(inti = L; I I--) sa[cnta[ch[i]]---] =i; rank[sa[1]] =1; for(inti =2; I ) {Rank[sa[i]]= Rank[sa[i-1]]; if(Ch[sa[i]]! = ch[sa[i-1]]) Rank[sa[i]] + +; } for(intL =1; Rank[sa[l]] 1){ for(inti =0; I 0; for(inti =0; I 0; for(inti =1; I ) {Cnta

();} while(ch>=' 0 'ch' 9 ') {x=x*Ten+ch-' 0 '; Ch=getchar ();}returnX*f;}CharSTR[MAXN];structsa{intRANK[MAXN],SA[MAXN],TSA[MAXN],A[MAXN],B[MAXN];intCNTA[MAXN],CNTB[MAXN];intheight[maxn],best[maxn][ -],n;//height[i]: CP of Sa[i] and Sa[i-1] voidGet () {N=strlen (str+1); Rep (I,0, -) cnta[i]=0; Rep (I,1, n) cnta[str[i]]++; Rep (I,1, -) cnta[i]+=cnta[i-1]; Rrep (I,n,1) Sa[cnta[str[i]]--]=i; rank[sa[1]]=1; Rep (I,2, N) {if(Str[sa[i]]==str[sa[i-1]]) {

]=maxlen[p]+1; while(P!ch[p][x]) ch[p][x]=np,p=Fa[p]; if(!p) fa[np]=1; Else { intq=Ch[p][x]; if(maxlen[p]+1==MAXLEN[Q]) fa[np]=Q; Else { intnq=++sz; memcpy (Ch[nq],ch[q],sizeof(Ch[q])); MAXLEN[NQ]=maxlen[p]+1; FA[NQ]=Fa[q]; FA[Q]=fa[np]=NQ; while(pch[p][x]==q) ch[p][x]=nq,p=Fa[p]; } } }}; Sam Sam;intMain () {CharCHR[MAXN]; intt,ans,i,l; scanf ("%d",T); while(t--) {sam.init (); Ans=0; scanf ("%s", CHR); L=strlen (CHR); for(i=0; i'A'); for(i=1; iSam.maxlen[

appears in a string that exceeds m (can be crossed), without output none, with the output length, and the last occurrence.Ideas:Find the suffix array, binary length, get the length, as for the last position, need to enumerate each position, that is greater than mid ht[i], corresponding to the sa[i], and sa[i-1].#include #include#include#include#include#includestring>#includeusing namespacestd;Const intmaxn=40010;CharCH[MAXN];intm;intMaxintXintY) {if(x>y)returnXreturny;}structsa{intRANK[MAXN],SA

"bzoj3238" [Ahoi2013] Difference descriptionInputOne line, a string sOutputA row, an integer that represents the value evaluatedSample InputCacaoSample Output WuExercisesWhat is the LCP of any two strings, just asA, b so if A==b is Len (a)Otherwise set sa[a]1#include 2#include 3#include 4#include 5#include 6 7 #defineN 5000078 #definell Long Long9 using namespacestd;TenInlineintRead () One { A intx=0, f=1;CharCh=GetChar (); - while(ch'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} -

Method for installing the R language package, r Language How to install the R package: 1. Online Installation On the R console, enter install. packages ("TSA") # install TSA Install. packages ("TSA", contriburl = "url", dependencies = TRUE) # install TSA 2. Manual installation (offline installation) In Wi

Zhangzhenhua on 2016/11/1. */public class Pdfsigner {//tsa private signerkeystore signerkeystore; Private Tsaclient tsaclient; Private Pdfsigner () {}/** * * @param tsa_url TSA server address * @param tsa_accnt TSA Account number * @param TSA_PASSW ts A password * @param cert_path certificate path * @param CERT_PASSW Certificate Password */public Pdfsigner

1. About this article When transmitting information using the TCP (class TcpClient), UDP (class UdpClient) protocol under C #, you need to convert the information to an array of type byte to send. This article implements two conversions of object and byte arrays and a way to convert a file to a byte array. Data of the underlying type, which can be converted using functions in the Bitconverter class. 2.object and byte[] conversion: Serialization and deserialization using IFormatter serialize and

EREP (i,u) for (register int i=head[u];~i;i=nxt[i])#define IIN (a) scanf ("%d", a)#define Lin (a) scanf ("%lld", a)#define DIN (a) scanf ("%lf", a)#define S0 (a) scanf ("%s", a)#define S1 (a) scanf ("%s", a+1)#define PRINT (a) printf ("%lld", (ll) a)#define ENTER Putchar ('\n ')#define Blank Putchar (")#define PRINTLN (a) printf ("%lld\n ", (ll) a)#define IOS ios::sync_with_stdio (0)using namespaceStdConst intMAXN =1e5+11;Const intOO =0x3f3f3f3f;Const DoubleEPS =1e-7;typedef Long LongLl;ll Read

#include #include #include #include #include #include #include #include #include #include #include #define REP (i,j,k) for (register int i=j;i#define RREP (i,j,k) for (register int i=j;i>=k;i--)#define EREP (i,u) for (register int i=head[u];~i;i=nxt[i])#define IIN (a) scanf ("%d", a)#define Lin (a) scanf ("%lld", a)#define DIN (a) scanf ("%lf", a)#define S0 (a) scanf ("%s", a)#define S1 (a) scanf ("%s", a+1)#define PRINT (a) printf ("%lld", (ll) a)#define ENTER Putchar ('\n ')#define Blank Putc

), x,tmp=0, ans=0; last=1; for(intI=0; i) {x=chr[i]-'a'; if(Ch[last][x]) tmp++,last=Ch[last][x]; Else { while(Last!ch[last][x]) last=Fa[last]; if(! Last) tmp=0, last=1; Elsetmp=maxlen[last]+1, last=Ch[last][x]; } ans=Max (ans,tmp); } printf ("%d\n", ans); }}; Sam Sam;intMain () {intt,i,l; while(~SCANF ("%s", CHR)) {Sam.init (); L=strlen (CHR); for(i=0; i'a'); Sam.solve (); } return 0;} View Codesuffix array: two strings need to be concatenated, plus a special symb

[MAXN],TSA[MAXN],A[MAXN],CNTA[MAXN],B[MAXN],CNTB[MAXN]; intht[maxn],min[maxn][ -],n; voidGet_sa () {N=strlen (ch+1); for(intI=0; i -; i++) cnta[i]=0; for(intI=1; i; for(intI=1; i -; i++) cnta[i]+=cnta[i-1]; for(inti=n;i>=1; i--) sa[cnta[ch[i]]--]=i; rank[sa[1]]=1; for(intI=2; i1]]+ (ch[sa[i]]==ch[sa[i-1]]?0:1); for(intL=1; rank[sa[n]]1){ for(intI=1; i0; for(intI=1; i; for(intI=1; i0]++; for(intI=1; i1],cntb[i]+=cntb[i-1]; for(int

tool, locate the following directory Meta-inf, delete the directoryEcho 6. If there is a warning that-tsa or-tsacert is not provided, the signature instruction is followed by-tsa Https://timestamp.geotrust.com/tsaEcho ===============================#获得当前路径cur_dir=$ (PWD)#需要签名的apk文件名File_name=$1#验证该apk文件是否存在if [!-e ${file_name}.apk];thenecho "Error:not fount ${file_name}.apk FILE"Exit 1Fi#查看指定apk的签名信息Echo V

, Sdib)Call CopyMemory (ByVal VarPtrArray (Sbits ()), VarPtr (Stsa), 4)'--Create new DIBCall Create (Newwidth, Newheight)Call PVBUILDSA (DtSA, Me)Call CopyMemory (ByVal VarPtrArray (Dbits ()), VarPtr (DtSA), 4)W = NewwidthH = NewheightFor y = 1 to H-1For x = 1 to W-1With Dbits (x, y)DXX = CInt (x * thetacos-y * thetasin + F1 + 0.5)Dyy = CInt (x * thetasin + y * thetacos + f2 + 0.5)If dxx > 0 and dyy > 0 and Dxx . B = Sbits (dxx, Dyy). B. G = Sbits (dxx, Dyy). G. R = Sbits (dxx, Dyy). RElse. B =

1. Generate key: Keytool-genkey-alias demo.keystore-keyalg rsa-validity 40000-keystore demo.keystore2. Signature file: Jarsigner-verbose-keystore demo.keystore-signedjar demo_signed.apk demo.apk demo.keystoreIf the installation fails, add the parameter "-digestalg sha1-sigalg Md5withrsa" after re-signing the installationIf not available-tsa or-tsacert, this jar does not have a timestamp. If there is no timestamp, the user may not be able to verify the

development process definition; During the software design phase, the architect is responsible for the entire software architecture, key artifacts, interface and development policy design; In the coding phase, the architect becomes the consultant of the detailed designer and code writer, and regularly holds some technical seminars, technical courses, etc. integration and test support will be the focus of the software architect as software begins testing, integration and delivery; When software

statistic, count the sum of the minimum of the interval of each number as the right endpoint, and add them up. Here is the use of a monotonous stack of a magical nature: a sequence is pressed into the monotone stack, the sequence of the suffix of the minimum/maximum value will be in the monotone stack appear. It can then be transformed into a statistical contribution to the sum of the minimum values for each number in the monotonic stack. The method of calculation is as below:Furthermore, since

InputJSOI07Sample OutputI0O7SJHINTThe length of the data string for 100% does not exceed 100000.After the able the group is not good to understand, can be directly back, anyway, I feel that the base number of the second half of the simple to understand.#include #include#include#include#include#include#include#includeSet>#include#include#includestring>#include#includeusing namespacestd; #ifdef WIN32#defineLL "%i64d"#else#defineLL "%lld"#endif#defineMAXN 110000#defineMAXV maxn*2#defineMaxe maxv*2