udemy data structures and algorithms

observers, that is, dependent objects, each time data changes, these 2 view will changeclassHexviewer (object):defUpdate (self, subject):Print 'hexviewer:subject%s has data 0x%x'%(Subject.name, Subject.data)classDecimalviewer (object):defUpdate (self, subject):Print 'decimalviewer:subject%s has data%d'%(Subject.name, Subject.data)if __name__=='__main__': Data1=

detection and re-hashing;2), Di = 12,-12,22,-22,32,..., ±k2 (K≤M/2), called two-time detection and re-hashing;3), Di = pseudo-random number sequence, called pseudo-random detection re-hash.(2), re-hash methodhi = RHI (key) i =,..., kRHI are different hash functions.(3), Chain address methodStores all the data elements of a synonym in the same linear list. Assuming that the hash address produced by a hash function is on the interval [0,m-1], a pointer

Algorithm Figure Search (breadth first, depth first) depth first is especially important Sort Dynamic planning Matching algorithm and network flow algorithm Regular expressions and string matching Data Figure (tree is particularly important) Map Heap Stack/queue Tries | Dictionary Tree Additional recommendations Greedy algorithm Probability method Approximate algorithm Algorithm: Three-way di

Today we will talk about how to calculate the complexity of time.The concept of Time complexity: (Baidu version)The same problem can be solved by different algorithms, and the quality of an algorithm will affect the efficiency of the algorithm and even the program.The purpose of the algorithm analysis is to select the suitable algorithm and the improved algorithm.In computer science, the time complexity of the algorithm is a function, which quantitati

fastest in the complexity of O (n^2);(2) Choose Sort, bubble sort is slow, usually appear in the interview question.Complexity of O (N*LOGN):(1) Quick sorting: Based on the comparison of the fastest in the ranking;(2) Merge sort: Less use in practice, often in interview;(3) Heap sorting: The actual use is less, but the heap is very common;The complexity is O (n), and only positive integers can be sorted:(1) Cardinal rank-complexity O (n+r), R as Radix;(2) Counting sort-complexity O (n+k), K for

Back to think of their own computer method surface knowledge system, can only be summed up with disunity. Decided to start from this blog, the accumulation of knowledge to do a comprehensive summary, re-think of their career planning and development.First, the basic data structure begins to comb.This is the first line of the plan.1. Work and project knowledge carding and summary(Sum up what you've done and what you've been doing these days)2. Individu

ordered data function List () {this.listsize = 0; this.pos = 0; this.datastore = []; this.find = Find, ..............} Method: Append: ... Read the full text posted @2014-10-13 09:31jinkspeng read (+) | Comments (0) Edit NBSP;JS: Data structure NOTE 1---An array summary: JS Array: Just a special object, less efficient than other languages; A property is an index used to represent an offset; in JS, a numer

result.So what do we do with the program language output?int sum =0,n = 100;for (int i=1;i{Sum =sum+i;}coutGaussian algorithmint i,sum=0,n=100;sum = (1+n) *N/2;cout Execute only onceWhat is an algorithm?A description of the solution steps for a specific problem, represented as a finite sequence of instructions in the computer, and each instruction represents one or more operationsFive basic featuresInput, output, poor, deterministic and feasibleInputAlgorithm Local area 0 or more inputsvoid Tes

A data structure is a collection of one or more specific relationships that exist between each other.The popular point is the logical structure of the data, such as what kind of structure the data is stored in memory.General data structures: arrays, linked lists, trees, hash

5277,59350,53353,68663,9642,30406,5396,3222,67194,7124,54247,15077,97688,36939,62888,80307,65467,6882,97071,39652,38268,8 8226,89088,92198,39003,9858,73803,83078,24648,49891,34551,57649,24443,30685,68740,55407,53155,87465,89282,41856,96218,372 92,24551,67663,31715,46363,25573,61921,56333,69576,55919,19818,26409,21590,70392,67648,36909,89175,74443,41856,11755,2478 8,25975,25116,57360,80998,62093,40691,91189,29337,68914,57653,64272,53653,5975,27967,59600,25803,13937,93725,26457,16603 , 18360,7992

Chapter 6 of Robert lafore, Java data structures and algorithms /* 6.1 assume that you have bought a cheap handheld computer, but find that its built-in chip cannot be used for multiplication and can only be used for addition. To get rid of this dilemma, you need to write your own program, write a recursive method mult (), and its parameter number is X and the re

Data Structure : There is a relationship between the two;algorithm : A description of the steps of the problem solving, represented in the computer as some column instructions and operationsalgorithm Five features : input (input parameters), output (results obtained), certainty (step is meaningful without ambiguity), feasibility (each step is feasible) correctness (in addition to the previous features, it also has the need to reflect the problem and g

Recommend a Visual Web site "Visual Algo": Url= ' https://visualgo.net/en/sorting 'This website gives the principles and processes of various sorting algorithms, which are visualized through dynamic forms. The related pseudo-code are also given, as well as the specific steps to execute to code."Bubble Sort"You need to repeatedly visit the sequence of columns that need to be sorted. The size of the adjacent two items is compared during the visit, and i

); For (uint I = 0; I { Tree childTree = headTree [I]; If (! ChildTree. IsEmpty ()) TmpQueue. Enqueue (childTree ); } } } // -------------------------------------------------- End ------------------------------------ // The internal Member class is used to provide visitors of different traversal types. Public class PreOrder: IPrePostVisitor { Private IVisitor visitor; Public PreOrder (IVisitor _ vis) {visitor = _ vis ;} # Region IPrePostVisitor Member Public void PreVisit (object _ obj) {

("Lookup data does not exist"); the return NULL; the } + -System.out.println ("Find successful, data is:" + This. list[p]); the return This. list[p];Bayi } the the //Sequential Table Size - Public intSizeOf () { - return This. Listlen; the } the the Public voidPrint () { theSystem.out.print ("["); - for(inti = 0; I This. list.length;

;}/* Loop to delete the queue node */while (P.LINK!=P){for (i=0;i{R=p;P=p.link;}R.link=p.link;Console.WriteLine ("deleted element: {0}", P.data);Free (p);P=r.node.;}Console.WriteLine ("\ n the last element removed is: {0}", P.data);The specific algorithm:650) this.width=650; "Width=" 620 "height=" 420 "src=" http://files.jb51.net/file_images/article/201211/ 2012110120510432.png "/>The complexity of the time of this algorithm is O (n2)}Reference: http://www.jb51.net/article/31698.htmThis article

= {'x': 1,'Z': 3}b= {'y': 2,'Z': 4 } fromCollectionsImportCHAINMAPC=Chainmap (A, b)Print(c['x'])#Outputs 1 (from a)Print(c['y'])#Outputs 2 (from B)Print(c['Z'])#Outputs 3 (from a)Idea 2:dict_bak.update ({new_dict}), update the original dictionary (copy), the original duplicate key's value will be overwritten, can only query to the new dictionary data, the original dictionary changes can not be reflected synchronouslyTest = Dict (a) #用dict生成原字典的副本

1 and 0 occurrences of the place, 1 and 0 appear two times, since there is no 0, then 1 is occupy the first and second position (please read this sentence carefully, this sentence read, the whole algorithm understand). Then we put one of the 1 in the position of the second position of the 1 b[1], while c[1]-1, because we have already lined up a 1.Next, I=1,a[1]=2,c[2] is less than or equal to 2 of the number of occurrences, c[2]=4, then to rank it in fourth place, that is b[3] position, while c

front end with techniques such as SVG. (Another scenario I came up with was to show a file tree like Windows Explorer on the front end)I thought for a long time, did not think of a circular solution, and later found the answer on the StackOverflow:var plain2Tree = function (obj) { var key, res for(key in obj) { var parent = obj[key].parent if(parent === ‘‘) { res = obj[key] } else { obj[parent][key] = obj[key] } } return res}This code is the use of JavaScript inside the reference type, then th

if(Head.next.data.equals (key)) { theSystem.out.print ("Query node:" + key + ","); theSystem.out.print ("Query node predecessor node is:" + Head.data + ","); the if(Head.next.next! =NULL) {98SYSTEM.OUT.PRINTLN ("Query node post node is:" +head.next.next.data); About}Else { -SYSTEM.OUT.PRINTLN ("Query node is tail node!"));101 }102 return;103 }104Head =Head.next; the }106System.out.println ("No this node!"));107