05-Tree 8 File Transfer (25 min)

Source: Internet
Author: User

05-Tree 8 File Transfer (25 min)

We have a network of computers and a list of bi-directional connections. Each of the these connections allows a file transfer from one computer to another. Is it possible to send a file from any computer on the network to any other?

Input Specification:

Each input file contains the one test case. For each test case, the first line containsN2≤ n≤1 0 ? 4 ?), the total number of computers in a network. Each computer in the network are then represented by a positive integer between 1 and n. Then in the following lines, the input was given in the format:

I c1 c2  

Where I stands for inputting a connection between c1 and c2 ;

C c1 c2    

Where C stands for checking if it's possible to transfer files between c1 and c2 ;

S

Where stands for stopping the this case S .

Output Specification:

For each case, print on one line C the word "yes" or "no" if it's possible or impossible to transfer files between c2 and, respectively. At the end of all case, print on one line ' the network is connected. ' If there is a path between any pair of computers; Or "There is a." Where is the number of k k connected.

Sample Input 1:
5C 3 2I 3 2C 1 5I 4 5I 2 4C 3 5S
Sample Output 1:
nonoyesThere are 2 components.
Sample Input 2:
5C 3 2I 3 2C 1 5I 4 5I 2 4C 3 5I 1 3C 1 5S
Sample Output 2:
nonoyesyesThe network is connected.


特意查了查c++的 二维数组 怎么声明 ,函数 参数是二维数组的情况怎么做,返回是一维数组怎么弄,
查到用的是指针.就那么用吧,估计就该这样吧.

c#的代码不能满分
c++的可以

usingSystem;usingSystem.Collections.Generic;usingSystem.Threading;usingSystem.Threading.Tasks;usingSystem.Diagnostics;usingSystem.Net;usingSystem.Text;usingSystem.Xml;classt{ Public classmyitem { Public intValue;  Public intPindex; }    Static voidMain (string[] args) {List<MyItem> list =NewList<myitem>(); varCount =int.        Parse (Console.ReadLine ());  for(inti =1; I < Count +1; i++) {list. ADD (NewMyItem () {Value = i, Pindex =-1 }); } AAA:varA =Console.ReadLine (); if(A! ="S")        {            varItem = A.split (' '); varV1 = lookup (list, item[1]); varV2 = lookup (list, item[2]); Switch(item[0])            {                 Case "C":                    if(v1. Value = =v2. Value) {Console.WriteLine ("Yes"); }                    Else{Console.WriteLine ("No"); }                     Break;  Case "I":                    if(v1. Pindex <=v2. Pindex) {v1. Pindex+=v2.                        Pindex; V2. Pindex=v1.                    Value; }                    Else{v2. Pindex+=v1.                        Pindex; V1. Pindex=v2.                    Value; }                     Break; default:                     Break; }            GotoAAA; }        Else        {            varv = list. FINDALL (ax = ax). Pindex <0); if(V.count = =1) {Console.WriteLine ("The network is connected."); }            Else{Console.WriteLine ($"there is {v.count} components."); }            return; }    }    Private StaticMyItem Lookup (list<myitem> List,stringItem) {        varMyItem = list[int. Parse (item)-1]; if(MyItem! =NULL)        {             while(Myitem.pindex >0) {myitem= list. Find (x = X.value = =Myitem.pindex); }            returnmyitem; }        Else        {            return NULL; }    }}

 
//C1.cpp: This file contains the "main" function. The execution of the program starts here and ends here. ////#include "pch.h"#include <iostream>using namespacestd;int* FIND (int**list,inti1);intCCC =0;intMain () {int**list; Std::cin>>CCC; List=New int*[CCC];  for(inti =0; I < CCC; i++) {List[i]=New int[2]; list[i][0] = i +1; list[i][1] = -1; }AAA:CharA ='a'; Std::cin>>A; if(A! ='S')    {        intI1; intI2; Std::cin>>I1; Std::cin>>I2; int*V1 =Find (list, i1); int*v2 =Find (list, i2); Switch(a) { Case 'C':            if(v1[0] = = v2[0]) {cout<< ("yes\n"); }            Else{cout<< ("no\n"); }             Break;  Case 'I':            if(v1[1] <= v2[1]) {v1[1] + = v2[1]; v2[1] = v1[0]; }            Else{v2[1] + = v1[1]; v1[1] = v2[0]; }             Break; default:             Break; }        GotoAAA; }    Else    {        intCI =0;  for(inti =0; I < CCC; i++)        {            if(list[i][1] <0) {ci++; }        }        if(CI = =1) {cout<< ("The network is connected.\n"); }        Else{cout<<"there is"<< ci <<"components.\n"; }    }    return 0;}int* FIND (int**list,intI1) {    inti = I1-1;  for(; i < CCC; i++)    {        if(list[i][0] ==I1) {             Break; }    }     while(list[i][1] >0) {i= list[i][1] -1; }    returnlist[i];}

 

05-Tree 8 File Transfer (25 min)

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