1002. Write this number (20) (zjupat)

Link: http://pat.zju.edu.cn/contests/pat-b-practise/1002

Read a natural number N, calculate the sum of all its numbers, and write each digit in Chinese pinyin.

Input Format:Each test input contains one test case, that is, the value of natural number n. N must be less than 10100.

Output Format:Output each digit of N in a row. There is a space between the pinyin numbers, but there is no space after the last pinyin number in a row.

Input example:

1234567890987654321123456789

Output example:

yi san wu

The Code is as follows:

#include <cstdio>#include <cstring>typedef long long LL;const int MAXN = 117;char s[MAXN];char num[10][7] = {"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};int ans[MAXN];LL sum;void Print(){    int l = 0;    while(sum > 0)    {        int tt = sum%10;        ans[l++] = tt;        sum/=10;        // printf("%c\n",ans[l-1]);    }    for(int i = l-1; i > 0; i--)    {        printf("%s ",num[ans[i]]);    }    printf("%s\n",num[ans[0]]);}int main(){    while(gets(s))    {        int len = strlen(s);        sum = 0;        for(int i = 0; i < len; i++)        {            sum+=s[i]-'0';        }        //  printf("%I64d\n",sum);        Print();    }    return 0;}

1002. Write this number (20) (zjupat)