1144:0 start-up algorithm 51--the number of deletions in an array

Source: Internet
Author: User

1144:0 start-up algorithm 51--array delete time limit:1 Sec Memory limit:64 MB 64bit IO Format:%lld
submitted:3304 accepted:933
[Submit] [Status] [Web Board] Description

Deletes a number in the given array

Input

Multiple sets of tests, enter 1 integers n (n<20) and then n integers in the first row of each group
Enter 1 integer m in the second line

Output

Delete the first number m in the first row of n integers and delete and then output the remaining number in sequence,

Sample Input
4 1 2) 3 43

Sample Output
1 2 4

HINT

M may not be found in the original array, output original array is not found


Source

0 Starting point Learning algorithm

1#include <stdio.h>2 intMain () {3     intn,a[ -];4      while(SCANF ("%d", &n)! =EOF) {5          for(intI=0; i<n;i++){6scanf"%d",&a[i]);7         }8         9         intm,t,sign=1;Tenscanf"%d",&m); One          for(intI=0; i<n;i++){ A             if(m==A[i]) { -t=i; -sign=0; the                  Break; -             } -         } -          +         if(sign) { -              for(intI=0; i<n-1; i++){ +printf"%d", A[i]); A             } atprintf"%d\n", a[n-1]); -         } -         Else{ -              for(intI=0; i<t;i++){ -printf"%d", A[i]); -             } in              for(intj=t+1; j<n-1; j + +){ -printf"%d", A[j]); to             }  +printf"%d\n", a[n-1]); -         }  the     } *     return 0; $}

Feel a problem if the number of deletions is the last one??

1144:0 start-up algorithm 51--the number of deletions in an array

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