11th Week Reading Procedure (supplement)----(2)

Questions and codes:

/* *copyright (c) 2016, Yantai University School of computer *all rights reserved. * File name: Zwj.cpp * Author: Zhang Weijing * Completion date: May 10, 2016 * Version number: v1.0 * * Problem Description: Read program * Input Description: * Program output: */#include <iostream>using Namespac    E std;class a{private:int x;protected:int y;public:int z;        A (int a,int b,int c) {x=a;        Y=b;    Z=c;    } int Getx () {return x;}    int Gety () {return y;}        void ShowA () {cout<< "x=" <<x<< ' \ t ';        cout<< "y=" <<y<< ' t ';    cout<< "z=" <<z<< ' \ n ';        }};class B:public A//modify point (see following reading requirements) {Private:int m,n;public:b (int a,int b,int c,int d,int E): A (a,b,c) {        M=d;    N=e;        } void Show () {cout<< "m=" <<m<< ' \ t ' << "n=" <<n<< ' \ n ';        cout<< "x=" <<getx () << ' t ';    cout<< "y=" <<y<< ' \ t ' << "z=" <<z<< ' \ n ';    } int Sum () {return (Getx () +y+z+m+n);    }};int Main () {B B1 (1,2,3,4,5);B1.    ShowA (); B1.    Show (); cout<< "sum=" <<b1.    Sum () << ' \ n '; cout<< "x=" <<b1.    Getx () << ' \ t '; cout << "y=" <<b1.    Gety () << ' \ t ';    cout << "z=" <<b1.z<< ' \ n '; return 0;}

Expected Result:

X=1 y=2 z=3

X=1 y=2 z=3

M=4 n=5

X=1 y=2 z=3

Sum=15

X=1 y=2 z=3

Operation Result:

Process Analysis:

First initialize the object of B B1, assign the variables, then B1.showa (), Output x=1 y=2 z=3, then b1.show () output m=4 n=5 x=1 y=2 z=3, then output sum =15, x=1 y =2 z=3

11th Week Reading Procedure (supplement)----(2)