17th Week Item 4-date structure (the day ordinal of the year)

Defines a struct variable (including year, month, and day) that requires the input of the year, month, and day, which is the day ordinal of the year.

/** Copyright (c) 2014, Yantai University School of Computer * All right reserved.* Shao * file: demo.cpp* finish: December 16, 2014 * version number: v1.0*/#include <iostream    >using namespace std;struct date{int year;    int month; int day;};    int main () {date date;    cout<< "input year,month,day:";    cin>>date.year>>date.month>>date.day;    int days;        Calculate days switch (date.month) {case 1:days = Date.day;    Break        Case 2:days = Date.day + 31;    Break        Case 3:days = Date.day + 59;    Break        Case 4:days = Date.day + 90;    Break        Case 5:days = Date.day + 120;    Break        Case 6:days = date.day + 151;    Break        Case 7:days = date.day + 181;    Break        Case 8:days = date.day + 212;    Break        Case 9:days = date.day + 243;    Break        Case 10:days = date.day + 273;    Break        Case 11:days = date.day + 304;    Break        Case 12:Days = Date.day + 334;    Break } if ((date.year% 4 = = 0 && date.year% 100! = 0) | |    (date.year% = = = 0 && date.year 100 = = 0))    {if (date.month>2) days--; } cout<<date.month<< "Month" <<date.day<< "Day is" <<date.year<< "year" <<days< < "day."    <<endl; return 0;}

Operation Result:

@ Mayuko

17th Week Item 4-date structure (the day ordinal of the year)