2.3.1 Basic data types and operators

1 in the C language, the operator that requires the operand to be an integral type is %

　　2 int i = j = 5;→ This definition method is wrong :Note:each Undeclared identifier is reported only once for each func tion it appears in. /* int i =5, j = 5; */

3 Copy the larger number of integral type, a, to int c:c = (a>b)? a:b;√

4 in the C language, backspace is \b:

　　5 int a = 7; float x = 2.5,y = 4.7; The value of the expression x + a% 3 * (int) (x + y)% 2/4 is: 2.50000

6 int x, I, J, K; Then x = (i = 4, j = +, k = 32); The value of X is: 32

1 intMain ()2 {3     intx,j,i,k;4x = (i =4, j = $, k = +);5printf"%d", x);6 return 0;7     8     }9 /*output result is*/

7 int x = 8, y = 3; ask printf ("x = 8,y = 3\n x--:%d,--y:%d\n", x--,--y); What is the output of the result?

 int  x = 8 , y = 3  ; printf (  x = 8,y = 3\n x--:%d,--y:%d\n     , x--,--y);  int  a = 8 , B = 3  ; printf (  a = 8,b = 3\n a++:%d,++b:%d\n  , A++,++b);  /*   result: x = 8,y = 3 X--:8,--y:2a = 8,b = 3 A++:8,++b:4  */ 

8 is provided with an int a = 1,b = 2,c = 3, d = 4, m = 2,n = 2; then execute the statement (M = a > B) && (n = c > D); the value after N:

int 1 2 3 4 2 2 ;    = a > B) && (n = c > d);   printf ("%d"/* results are 2* /

9 known int a = 6; , A + = a-= A*a is executed; After, the value of a is:

    int 6 ;     + = A-=A * A;    printf ("A has the value:%d\n"  , a); /* */

Ten int x = 1,y = 1, z = 1; Execute Statement ++x | | + + y && ++z; After, find the value of the expression x + Y: 3

intx =1, y =1, z =1; intk = ++x | | ++y && + +Z; printf ("k = ++x | | ++y && ++z, k =%d\n", K); printf ("x =%d\n", x); printf ("y =%d\n", y); printf ("x+y =%d\n", x+y); intj = ++y && + +Z; printf ("j = ++y && ++z, j =%d\n", J); printf ("x =%d\n", x); printf ("y =%d\n", y); printf ("x+y =%d\n", x+y);/*k = ++x | | ++y && ++z, k = 1x = 2y = 1x+y = 3 J = ++y && ++z, j = 1x = 2y = 2x+y = 4*/ 　　 

2.3.1 Basic data types and operators