7. List

List is ordered, starting from 0 to Length-1

What the list can do: index, slice, add, multiply, check members.

1. Create a list

1 list = ['google'roob', 1997, +]   # can contain different data types

2. Access the values in the list

Use subscript index or square brackets to intercept characters

List1 = ['Google'YouTube', 1990= [ 1,2,3,4,5,6,7,8,9]print(list1[0])  #Googleprint#  [2, 3, 4, 5]

3. Update the list

List1 = ['Google'YouTube', 1990]Print (list1[0])  #Google"char"print(list1[0 ])  #Char

4. Delete List

List1 = ['Google'YouTube', 1990]Print (List1)  #[' Google ', ' YouTube ', 1990,]del  list1[0]  Print(list1)  #[' YouTube ', 1990]

5. List Footstep operator

Print(Len ([+]))#Length: 3Print([1,2,3]+[4,5,6])#combination: [1, 2, 3, 4, 5, 6]Print(["Google"]*4)#repeat: [' Google ', ' Google ', ' Google ', ' Google ']Print(3inch[+/-])#element is present in the list: True forIinch[A]:    Print(i)#iteration of the generations

6. Interception and splicing

L = ["Google","YouTube","Facebook"]Print(L[2])#FacebookPrint(L[-2])#YouTubePrint(l[1:])#[' YouTube ', ' Facebook ']s = [1,2,3,4]Print(L+s)#[' Google ', ' YouTube ', ' Facebook ', 1, 2, 3, 4]

7. Nesting

8. Functions

L = [n/a = (#)#The number of elements in the Len list is print#  3#  List of the largest elements print#3# list min and element print  #1# convert tuples to list print#[1, 2, 3]

9. Methods

L = [n/A]#add an object at the end of the listL.append (8)Print(l)#[1, 2, 3, 8]#Count the number of occurrences of an element in a listPrint(L.count (1))#1#append multiple values of another sequence at the end of a listL.extend ([A])Print(l)#[1, 2, 3, 8, 1, 2, 3]#finds the first occurrence of a specified value in a list, specifying the start and end position of the queryPrint(L.index (2))#1Print(L.index (2,2,6))#5#inserts an element at the specified position in the listL.insert (0,9)Print(l)#[9, 1, 2, 3, 8, 1, 2, 3]#removes an element from the list, defaults to the last element, and returns the value of the element, or you can specify a location to remove the elementS1 =L.pop ()Print(S1)#3Print(l)#[9, 1, 2, 3, 8, 1, 2]S2 =l.pop (0)Print(S2)#9Print(l)#[1, 2, 3, 8, 1, 2]#removes the element that matches the first element in a listL.remove (2)Print(l)#[1, 3, 8, 1, 2]#Reverse list ElementsL.reverse ()Print(l)#[2, 1, 8, 3, 1]#SortL.sort ()Print(l)#[1, 1, 2, 3, 8]#Copy Lists =l.copy ()Print(s)#[1, 1, 2, 3, 8]#Clear Listl.clear ()Print(l)#[]

　　

7, List