886A. ACM icpc# mean distribution problem (violence)

Title Source: Http://codeforces.com/problemset/problem/886/A

The main topic: Six people are known to score, ask whether it can be divided into two three team to make each team score plus and equal

#include <stdio.h>//Choose from six numbers of three non-repeating numbers plus sum if this sum is exactly half of the totalintMain () {inta[6]; inti,j,k,sum=0, S;  for(i=0;i<6; i++) {scanf ("%d",&A[i]); Sum+=A[i]; }     for(i=0;i<6; i++)         for(j=i+1;j<6; j + +)             for(k=j+1;k<6; k++) {s=a[i]+a[j]+A[k]; if(s==sum-s) {printf ("yes\n"); return 0; }} printf ("no\n"); return 0;}

Data is small, add to 6 people, and then enumerate any three people, if the sum is half of

886A. ACM icpc# mean distribution problem (violence)