9.21-width string Speech Recognition

Width:

 
 

  
  
#define _CRT_SECURE_NO_WARNINGS
  
  
#include <stdio.h>
  
  
#include <string.h>
  
  
#include <locale.h>
  
  
int main()
  
  
{
  
  
Char STR [10] = "xuanyuan ";
  
  
printf("%d,%d\n", sizeof(str), strlen(str));//10,4
  
  
Printf ("% d \ n", sizeof (""); // 5
  
  


  
  
Printf ("% C \ n", STR [0], STR [1]); // Xuan
  
  
Printf ("% C \ n", STR [0], STR [1]); // garbled
  
  


  
  
Printf ("% d, % d \ n", sizeof ("hello"), sizeof (L "hello"); // 6 12

  
  


  
  
Char * P = "Hello tianchao ";
  
  
Wchar_t * PW = l "Hello tianchao ";
  
  
Printf ("% s \ n", P); // Hello tianchao
  
  

  
  
// Error output of wide characters:
  
  
Printf ("% s \ n", PW); // H (incorrect output)
  
  
Printf ("% ls \ n", PW); // Hello (incorrect output)
  
  
Printf (L "% s \ n", PW); // No output
  
  
Printf (L "% ls \ n", PW); // No output
  
  

  
  
// Correct output:
  
  
// 1: must contain locale. H 2: Must be set local language 3: ls is to process wide characters
  
  
Setlocale (lc_all, "ZH-CN"); // Simplified Chinese
  
  
Printf ("% ls \ n", PW); // Hello tianchao (note that this sentence can be correctly printed in setlocale)
  
  
Wprintf (L "% ls \ n", PW); // Hello tianchao
  
  
return 0;
  
  
}
 
 

Wide character strlen sizeof:

 
 

  
  
#define _CRT_SECURE_NO_WARNINGS
  
  
#include <stdio.h>
  
  
#include <string.h>
  
  
int main()
  
  
{
  
  
Wchar_t wstr [10] = l "Liu Wei ";
  
  
printf("%d\n", sizeof(wstr));//20
  
  
printf("%d\n", strlen(wstr));//4
  
  

  
  
Printf ("% d \ n", sizeof ("Liu Wei"); // 5
  
  
Printf ("% d \ n", strlen ("Liu Wei"); // 4
  
  

  
  
Printf ("% d \ n", sizeof (L "Liu Wei"); // 6
  
  
Printf ("% d \ n", strlen (L "Liu Wei"); // 4
  
  

  
  
return 0;
  
  
}
 
 

From Weizhi note (wiz)

9.21-width string Speech Recognition