A few words to master subnet mask, IP address, host number, network number, network address, broadcast address

A few words to master subnet mask, IP address, host number, network number, network address, broadcast address

1, 191.172.16.10.33/27 in the/27 that is, the subnet mask is 255.255.255.224 that is 27 full 1

2. From the subnet mask 255.255.255.252 to obtain its network bit is 30 bits, so only the remaining 2-bit master, the host bit of all zeros for the network address, the host bit all 1 is the broadcast address, the remaining host number is the host address range

3. Public address is the responsibility of the Inter NIC (Internet Network Information Center Internet Information Center). These IP addresses are assigned to organizations that register and apply to the inter NIC. Direct access to the Internet through it.

Private address is a non-registered address and is intended for use within an organization. Private network IP address is not directly used to communicate with the WAN, or use the frame to communicate (for example, fr Frame Relay, HDLC,PPP) or need to route the NAT function to convert the private network address to a public IP address listed below the retained internal private address

Class A 10.0.0.0--10.255.255.255

Class B 172.16.0.0--172.31.255.255

Class C 192.168.0.0--192.168.255.255

Exercises:
IP address =192.168.127.101, subnet mask 255.255.255.192, compute network address, host number, broadcast address, and host maximum number

IP address converted to binary after 11000000.10101000.011111111.01100101

The subnet mask is converted to binary 11111111.11111111.11111111.11000000
The address segment is 11000000.10101000.01111111.01000000 after the operation.
The 192.168.127.64 is converted into decimal.
So the network address of this computer is 192.168.127.64/26
The host number is the part that removes the network number is 100101---->37
The broadcast address is the address bit all 1, i.e. 11000000.10101000.011111111.01111111
Converted to decimal after 192.168.127.127
The number of hosts that can be accommodated is 2 6 (number of host addresses) minus 2 (network address and broadcast address) =62

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A few words to master subnet mask, IP address, host number, network number, network address, broadcast address