When the read permission problem occurs, TFS will perform read-only processing on the file, so that the following exception occurs when ASP. NET development server uses filemode. Open.
"/" Application Program Server error.
Access to the path "E: \ mycsharpproject \ projects \ tfs.10.0.6.41 \ configs \ menuitems. xml" is denied.
Note:An unhandled exception occurred during the execution of the current Web request. Check the stack trace information to learn about this error andCodeDetailed information about the cause of the error.
Exception details:System. unauthorizedaccessexception: access to the path "E: \ mycsharpproject \ projects \ tfs.10.0.6.41 \ configs \ menuitems. xml" is denied.
ASP. NET does not have access to the requested resource. Consider granting the ASP. NET Request identity the permission to access this resource. ASP. net has a base process ID (usually {MACHINE} \ ASPnet on IIS 5 and serves the network on IIS 6 and IIS 7) that is used when the application is not simulated, ID of the configured application pool on IIS 7.5 ). If the application is simulating through <identity impersonate = "true"/>, the identity will be an anonymous user (usually IUSR_machinename) or an authenticated user.
To grant ASP. NET access permissions to a file, right-click the file in resource manager, select "properties", and select the "Security" tab. Click Add to add an appropriate user or group. Highlight the ASP. NET account and select the corresponding access permission box.
Source error:
Row 15: xmlserializer serializer = new xmlserializer (typeof (t); Row 16: // using (filestream = new filestream (xmlfilepath, filemode. open, fileaccess. read, fileshare. read) Row 17: Using (filestream = new filestream (xmlfilepath, filemode. open) Row 18: {row 19: Return serializer. deserialize (filestream) as t;
Source file:E: \ mycsharpproject \ projects \ tfs.10.0.6.41 \ utility \ xmlhelper. CSRow:17
Solution:
Modify the code:
Using (filestream = new filestream (xmlfilepath, filemode. Open, fileaccess. Read, fileshare. Read ))
You can.