Acm:hdu 2199 Can You solve this equation? Problem solving report-two points, three points

Can You Solve ThisEquation?Time Limit: -/ +MS (java/others) Memory Limit:32768/32768K (java/Others) Total submission (s):16281Accepted Submission (s):7206problem Descriptionnow,given the equation8*x^4+7*x^3+2*x^2+3*x +6= = Y,can you find its solution between0and -; nowTryyour lucky. Inputthe first line of the input contains an integer T (1<=t<= -) which means the number of test cases. Then T lines follow, each line has a real number Y (Fabs (Y) <=1e10); Outputfor each test Case, you should just output one real number (accurate4 decimalPlaces), which isThe solution of the Equation,or "No solution!",ifThere isNo solution forThe equation between0and -. Sample Input2 --4Sample Output1.6152No Solution!Authorredow Recommendlcy

Math problem, direct binary, code

1#include"iostream"2#include"algorithm"3#include"Cstdio"4#include"CString"5#include"Cmath"6 #defineMax (A, b) a>b?a:b7 #defineMin (A, b) a<b?a:b8 #defineMX 10000 + 509 using namespacestd;Ten  One DoubleFDoublex) A { -     return  8*pow (x,4)+7*pow (x,3)+2*pow (x,2)+3*x+6; - } the  - intMain () - { -     intN; +     Doublem; -      while(~SCANF ("%d",&N)) +     { A          for(intk=1; k<=n; k++) at         { -scanf"%LF",&m); -  -             DoubleI=0.0; -             if(M<f (0)|| M>f ( -)) -             { inprintf"No solution!\n");Continue; -             } to             DoubleFr=0.0, ed=100.0; +              for(; Fabs (F (FR)-F (ed)) >1e-4;) -             { theI= (fr+ed)/2; *                 if(f (i) <m) fr=i; $                 ElseEd=i;Panax Notoginseng             } -             { theprintf"%.4lf\n", i); +             } A         } the     } +     return 0; -}

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Acm:hdu 2199 Can You solve this equation? Problem solving report-two points, three points