Adjust the array order so that the odd digits are preceded by even numbers

Enter an array of integers to implement a function that adjusts the order of the numbers in the array so that all the odd digits are placed in the first half of the array, all the even digits are located in the second half of the array, and the relative positions between the odd and odd, even and even, are guaranteed.

Idea: Similar to insert sort.

Package practice;

public class Test {
private static void Reorderarray (int[] arr) {

for (int i = 0; i < arr.length; i++) {
int a = Arr[i];
If (Arr[i]% 2 = = 1) {
if (i > 0) {
int temp = Arr[i];
for (int m = i; m >= 0; m--) {

If (arr[m-1]% 2 = = 0) {
ARR[M] = arr[m-1];
} else {
ARR[M] = temp;
Break
}

}
If (arr[0]% 2 = = 0) {
Arr[0] = Arr[i];
}

}

}

}

for (int i = 0; i < arr.length; i++) {

System.out.println (Arr[i] + "");
}

}
public static void Main (String args[]) {
Int[] array = {1,4,4,5,9,8};
Test test = new test ();
Test.reorderarray (array);
}
}

  Public voidReorderarray (int[] Array) {         for(inti = 0;i<array.length;i++){             for(intj = array.length-1;j>i;j--){            if(array[j-1]%2 = = 0&&array[j]%2 = = 1){                inttemp = 0; Temp= Array[j-1]; Array[j-1] =Array[j]; ARRAY[J]=temp; }            }        }    }     }

Adjust the array order so that the odd digits are preceded by even numbers