Android: & gt; use of symbols and & amp; To obtain actio under multi-touch

/**
* This method is used to convert between hexadecimal, binary, hexadecimal, and decimal.
* @ Param args
*/
// The following is a binary conversion hexadecimal table.
// 0001 1 1000 8 1111 F
// 0010 2 1001 9
// 0011 1010
// 0100 4 1011 B
// 0101 1100 C
// 0110 6 1101 D
// 0111 7 1110 E
Public static void main (String [] args ){
// Decimal 261
Int x = 261; // convert to hexadecimal: 105 261/16 105 = 16 to 5 16 = 10 10 splice the remainder 5 =
// 105: 0000 0001 0000 0101
// Ff00: 1111 1111 0000 0000
// Result: 0000 0001 0000 0000
// >>> 8: 0000 0001
 
// 0x00000105 0x000000 0001 0000 0101
// 0x000000 0001 0000 0000
// 0x0000 0001 move the binary code eight places to the right
// 101/2 = 10 binary divided by 2 is equivalent to moving the binary code one bit to the right
 
Int y = 0xff00; // 0x is the prefix of the hexadecimal code. ff00 is converted to binary = 1111111100000000.
// & Binary bitwise AND OPERATION
// >>> This symbol indicates moving the specified number of digits to the right (8 digits)
Int z = (x & y) >>> 8;
// X = 261 SIXTEEN: 0105 binary: 0000000100000101
// Y = 0xff00: 16: ff00 binary: 1111111100000000
// After x & y, multiply the upper and lower values of x and y to get the result: 0000000100000000.
// Then: (x & y) >>> 8 shifted to the right, and 8 digits: 00000001
 
 
System. out. println ("finger number is" + z );
 
Int w = x & 0x00ff;
// X = 261 SIXTEEN: 0105 binary: 0000000100000101
// Y = 0x00ff: 16: ff00 binary: 0000000011111111
// After x & y is multiplied by x and y, the result is: 0000000000000101 the JVM automatically converts the binary into decimal.
 
System. out. println ("Finger action" + w );

}
 
Through the above operations, we have simplified the finger movement under multi-point touch to get the value we want.


From sharme's column