Application of single chip microcomputer interrupt

51 single-chip microcomputer:

P3.2 PIN is INT0 interrupt

P3.3 PIN is INT1 interrupt

Button P3.2 P3.3

Button low-level trigger:

while (pb0==0);

Delay ();

#include <reg51.h>#defineSEG P0//define seven-section display to Port 0sbit LED= p2^0;//define the LED light to connect to the P2.0Sbit com = p1^0;//Digital tube com PortSbit OC = p1^1;//Define 573 latch enable port, I am using the 573 drive 7 segment Digital tube voidDELAY10MS (intx);//declaring a delay function 10ms * x;sbit PB0=p3^2;//Button 0Sbit pb1=p3^3;//Button 1unsignedCharCode tab[Ten]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7c,0x07,0x7f,0x67};//Common CathodeMain () {OC=0;//latching 0, light digital tubecom =0;//Light segEA =1;//Total InterruptionEX0 =1;//External Interrupt INT0EX1 =1;//External Interrupt INT1TR0 =1;//Run int 0 InterruptTR1 =1;//Run INT1 InterruptTCON =0x05;//set the signal trigger mode to be negative edge trigger     while(1)     {            inti;  for(i=0;i<Ten; i++)//showing 0-9 (of previous){seg=Tab[i]; Delay10ms ( +);//Delay 0.4s

        }    }                 }                     voidMy_int0 (void) Interrupt0   //INT 0{inti;  while(pb0==0); Delay10ms ( -);  for(i=9; i>=0; i--)//For Loop display 9-0 (Next number){SEG=tab[i];//display Digital to seven-section displayDELAY10MS ( +);//Delay 0.4s       }                      }                     voidMy_int1 (void) Interrupt2          //INT 1{inti;  while(pb1==0); Delay10ms ( -);  for(i=0;i<Ten; i++) {LED=0; Delay10ms ( -); LED=1; Delay10ms ( -); }}/*delay function, delay approx. x*1ms*/voidDELAY10MS (intX//delay function Start{            inti,j;  for(i=0; i<x;i++)//count x times, delay x*10ms         for(j=0;j< -; j + +);//Count 1200 times, delay 10ms 1200*8us}

Application of single chip microcomputer interrupt