Array-08. String converted to decimal integer (15)

Enter a string ending with #, which requires filtering out all non-hexadecimal characters (not case), forming a new string representing a hexadecimal number, and then converting it to a decimal number after the output. If the first character of the filtered string is "-", it indicates that the number is negative.

Input format:

The input gives a non-empty string that ends with # in a row.

Output format:

Outputs the converted decimal number in a row. The title ensures that the output is within the long range.

Input Sample:

+p-xf4+-1!#

Sample output:

-3905

#include <iostream> #include <string>using namespace Std;int main () {    string s;    int i,sum=0;    BOOL Flag=false,f=false;    Getline (cin,s);    for (i=0;s[i]!= ' # '; ++i) {        if (s[i]== '-' &&!flag)            f=true;        else if (s[i]<= ' 9 ' &&s[i]>= ' 0 ') {            sum=sum*16+s[i]-' 0 ';            flag=true;        }        else if (s[i]<= ' F ' &&s[i]>= ' a ') {            sum=sum*16+s[i]-' a ' +10;            flag=true;        }        else if (s[i]<= ' F ' &&s[i]>= ' a ') {            sum=sum*16+s[i]-' a ' +10;            flag=true;        }    }    if (f)        sum=-sum;    cout<<sum<<endl;    return 0;}

Array-08. String converted to decimal integer (15)